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Variante senza forme quadratiche e tabella quadriche di rotazione, aggiunti quadrica di rotazione, cono e cilindro generalizzati #6
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@@ -28,7 +28,7 @@ | |
\input{teoria/2.gram-schmidt.tex} | ||
\input{teoria/2.proiezioni-ortogonali.tex} | ||
\input{teoria/2.matrici-ortogonalmente-diagonalizzabili.tex} | ||
\input{teoria/2.forme-quadratiche.tex} | ||
% \input{teoria/2.forme-quadratiche.tex} | ||
\input{teoria/2.coniche.tex} | ||
\input{teoria/2.quadriche.tex} | ||
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@@ -45,6 +45,8 @@ \section{Esercizi svolti} | |
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% | ||
\rule{0.3\linewidth}{0.25pt} | ||
\scriptsize\\ | ||
\href{mailto:[email protected]}{M. Donadoni}, \href{mailto:[email protected]}{E. Morassutto}, Politecnico di Milano, A.A. 2016/17 | ||
\href{mailto:[email protected]}{M. Donadoni}, \href{mailto:[email protected]}{E. Morassutto}, | ||
\href{mailto:[email protected],it}{Alessandro Fulgini} \\ | ||
Politecnico di Milano, A.A. 2016/17 | ||
\end{multicols} | ||
\end{document} |
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\begin{multicols}{2} | ||
\textbf{Cono generalizzato}: \\ | ||
$\begin{cases} | ||
\overrightarrow{VP}=t\cdot\overrightarrow{VP_{0}}& P_{0}\in \mathfrak{C} \\ | ||
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There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. Posso consigliarti di inserire un breve paragrafo prima dei 3 sistemi che spieghi il significato di ogni "lettera" e, visto che adesso avanza tantissimo spazio, magari anche una spiegazione rapida del procedimento (es. per le quadriche di rotazione: si prende un punto generico sull'asse, si crea una sfera centrata in quel punto e con raggio uguale alla distanza dal centro al generico punto... ecc...) Visto che lo spazio non manca affatto togliendo la sezione sulle forme quadratiche sentiti libero di togliere le abbreviazioni che ho fatto. In molti esercizi, specie quelli di Marco, ho dovuto commentare molte frasi, se ti sembrano utili puoi decommentare quelle righe. |
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Q(\vec{x_{0}})=0 \\ | ||
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L(\vec{x_{0}})=0 \\ | ||
\end{cases}$ \\ | ||
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\textbf{Cilindro generalizzato}: \\ | ||
$\begin{cases} | ||
\overrightarrow{P_{0}P}=t\cdot\vec{v}& P_{0}\in \mathfrak{C} \\ | ||
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. Idem, |
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Q(\vec{x_{0}})=0 \\ | ||
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. Idem, |
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L(\vec{x_{0}})=0 \\ | ||
\end{cases}$ \\ | ||
\end{multicols} |
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\textbf{Quadrica di rotazione}: \\ | ||
$\begin{cases} | ||
\langle\vec{n},\overrightarrow{P_{0}P}\rangle=0 & \vec{n}$ asse di rotazione$\\ | ||
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. Ho definito una funzione apposta per il prodotto scalare, |
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d(P_{0},r)=d(P,r) & P_{0}\in \mathfrak{C}\\ | ||
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Q(\vec{x_{0}})=0 \\ | ||
L(\vec{x_{0}})=0 \\ | ||
\end{cases}$ \\ |
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\textbf{Rotazioni}: ($z = 0$) $F(x, y)$ attorno $x$ diventa $F(x, \sqrt{y^2+z^2})$ | ||
$F(x,y,z)$ è di rotazione $\Leftrightarrow$ ha 2 autoval uguali, diversi da 0. | ||
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\begin{tabular}{cccl} | ||
\textbf{Equazione} & \textbf{Asse} & \textbf{Risultato} & \textbf{Nome} \\ | ||
\hline | ||
$\frac{x^2}{a^2}+\frac{y^2}{b^2}=1$ & $x$ & $\frac{x^2}{a^2}+\frac{y^2+z^2}{b^2}=1$ & Ellis. di rot. \\ | ||
$\frac{x^2}{a^2}-\frac{y^2}{b^2}=1$ & $x$ & $\frac{x^2}{a^2}-\frac{y^2+z^2}{b^2}=1$ & Iperb. ellit. \\ | ||
$\frac{x^2}{a^2}-\frac{y^2}{b^2}=1$ & $y$ & $\frac{x^2+z^2}{a^2}-\frac{y^2}{b^2}=1$ & Iperb. iperb. \\ | ||
$x^2=2py$ & $x$ & $x^2+z^2=2py$ & Parab. di rot. | ||
\end{tabular} |
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Angolo & $\cos \theta = \frac{\product{\vec{u}}{\vec{v}}}{||\vec{u}||\,||\vec{v}||}$ \\ | ||
Dis. triangolare & $||\vec{u}+\vec{v}|| \le ||\vec{u}||+||\vec{v}||$ \\ | ||
Dist. punto-piano & $\frac{|ax_0 + by_0 + cz_0 + d|}{\sqrt{a^2 + b^2 + c^2}}$ \\ | ||
Dist. punto-retta & $||\vec{u} \times \overline{P_0Q}||$ ($\vec{u}$ versore di $r$, $Q \in r$) \\ | ||
Dist. punto-retta & $\frac{||\vec{u} \times \overline{P_0Q}||}{||\vec{u}||}$ \\ | ||
There was a problem hiding this comment. Choose a reason for hiding this commentThe reason will be displayed to describe this comment to others. Learn more. Mi sta bene accorciare così la formula ma occhio che adesso |
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Dist. retta-retta & $\frac{|\product{\overline{P_1P_2}}{\vec{r_1} \times \vec{r_2}}|}{||\vec{r_1} \times \vec{r_2}||}$ ($P_1 \in r_1$, $P_2 \in r_2$) | ||
\end{tabular} | ||
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Hey! Hey! Hey!
N. Cognome
è la forma corretta di inserire il proprio nome in questo foglio!