trying

js/filterLongWords.js

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+// ### filterLongWords.js
+// Write a program that will take an array of words. Using a variable called `maxLength`,
+//  push words that are less than the `maxLength` into a new array,
+//  and `console.log` the value of `maxLength`.
+//
+//  **Requirements**
+//  * Your array of words should be stored in a variable, which can be named whatever you like
+//  * `maxLength` should be a positive number
+
+
+var maxLength = 0;
+var maxPos = 0;
+var cities = ["Toronto", "Seoul", "Oslo", "Sydney"];
+var shortWordCities = []
+function remover(cities) {
+  for (var i = 0; i < cities.length ; i++) {
+    if (cities[i].length > maxLength) {
+      maxLength = cities[i].length;
+      maxPos = i;
+    }
+  }
+  for (var j = 0; j < cities.length; j++) {
+    if (cities[j].length < maxLength){
+      shortWordCities.push(cities[j]);
+    }
+  }
+}
+
+
+remover(cities);
+// console.log(shortWordCities);
+console.log(maxLength);

js/fizzbuzz.js

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+// ### fizzbuzz.js
+// Implement Fizz Buzz. Loop from 1 to 100.
+// If the number is divible by both 3 and 5,
+// print "fizzbuzz". Otherwise, if the number if divisible by 3,
+// print "fizz", or, if the number is divisible by 5,
+// print "buzz". If none of the above are true, print the number.
+// This is a very common interview question!
+
+
+function fizzBuzzLoop() {
+  // var output = " "
+    for(var i = 1; i <= 100; i++) {
+      if (i % 3 === 0 && i % 5 === 0) {
+        console.log("fizzbuzz");
+      } else if (i % 3 === 0) {
+        console.log("fizz");
+      } else if (i % 5 === 0) {
+        console.log("buzz");
+      } else {
+        console.log(i);
+      }
+    }
+ }
+
+fizzBuzzLoop();

js/grade.js

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+// ### grade.js
+// Write a program that will print the letter grade,
+// given a variable with a test score. Display either "A", "B", "C", "D", or "F",
+// for an score that is an integer between 0 and 100.
+//
+// **Requirements**
+// * Your program should have a variable to store the letter grade (an integer between 0 and 100)
+// * For the letter grades, you may use whatever grading scale you like
+// * You must use a switch statement (hint, you may need to review and think about how the `switch` statement works)
+
+// function yourGrade(score) {
+//
+//   switch(true) {
+//     case (score <= 100 && score >= 90):
+//        console.log('A');
+//         break;
+//     case (score <= 89 && score >= 80):
+//         console.log('B');
+//          break;
+//     case (score <= 79 && score >= 70):
+//         console.log('C');
+//          break;
+//     case (score <= 69 && score >= 60):
+//         console.log('D');
+//          break;
+//     case (score <= 59 && score >= 0):
+//       console.log('F');
+//   }
+// }
+//
+//
+// yourGrade(32);
+
+function yourGrade(score) {
+
+  switch(true) {
+    case (score <= 50):
+       console.log('F');
+        break;
+    case (score <= 60):
+        console.log('D');
+         break;
+    case (score <= 70):
+        console.log('C');
+         break;
+    case (score <= 80):
+        console.log('B');
+         break;
+    default:
+      console.log('A');
+      break;
+  }
+}
+
+
+yourGrade(91);

js/phonebook.js

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+// ### phonebook.js
+// Use a for...in loop to examine the phoneBook Object below and print out the names of all the people who share the phone number "333-333-3333".
+// ```
+var phoneBook = {
+  "Abe": "111-111-1111",
+  "Bob": "222-222-2222",
+  "Cam": "333-333-3333",
+  "Dan": "444-444-4444",
+  "Ern": "555-555-5555",
+  "Fry": "111-111-1111",
+  "Gil": "222-222-2222",
+  "Hal": "333-333-3333",
+  "Ike": "444-444-4444",
+  "Jim": "555-555-5555",
+  "Kip": "111-111-1111",
+  "Liv": "222-222-2222",
+  "Mia": "333-333-3333",
+  "Nik": "444-444-4444",
+  "Oli": "555-555-5555",
+  "Pam": "111-111-1111",
+  "Qiq": "222-222-2222",
+  "Rob": "333-333-3333",
+  "Stu": "444-444-4444",
+  "Tad": "555-555-5555",
+  "Uwe": "111-111-1111",
+  "Val": "222-222-2222",
+  "Wil": "333-333-3333",
+  "Xiu": "444-444-4444",
+  "Yam": "555-555-5555",
+  "Zed": "111-111-1111"
+};
+
+for (var name in phoneBook) {
+    if (phoneBook[name] === "333-333-3333") {
+        console.log(name);
+  }
+}

js/reverse.js

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+// ### reverse.js
+// Write a program that will take a hardcoded string, and console log the reversed version of it.
+//
+// **Requirements**
+// * You must use a `for` loop. No `.reverse()`
+// * You may use the string below
+
+var normal = 'building';
+function reverseString(normal) {
+var reversed = "";
+    for (var i = normal.length - 1; i >= 0; i--) {
+        reversed += normal[i];
+    }
+    console.log(reversed);
+}
+reverseString(normal);