js control flow completed assignment

js/filterLongWords.js

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+// ### filterLongWords.js
+// Write a program that will take an array of words. Using a variable called `maxLength`, push words that are less than the `maxLength` into a new array, and `console.log` the value of `maxLength`.
+//
+// **Requirements**
+// * Your array of words should be stored in a variable, which can be named whatever you like
+// * `maxLength` should be a positive number
+
+
+var maxLength = 4
+var input = ['how', 'was', 'your', 'day']
+var short = []
+
+// console.log(input[0].length)
+for (i = 0; i < input.length; i++) {
+  if (input[i].length < maxLength) {
+    short.push(input[i])
+  }
+}
+
+console.log(short, maxLength)

js/fizzbuzz.js

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+// ### fizzbuzz.js
+// Implement Fizz Buzz. Loop from 1 to 100. If the number is divible by both 3 and 5, print "fizzbuzz". Otherwise, if the number if divisible by 3, print "fizz", or, if the number is divisible by 5, print "buzz". If none of the above are true, print the number. This is a very common interview question!
+
+for (i = 1; i <= 100; i++) {
+  if (i % 3 === 0 && i % 5 === 0){
+    console.log("fizzbuzz")
+  }
+  else if (i % 3 === 0 && i % 5 !== 0){
+    console.log("fizz")
+  }
+  else if (i % 3 !== 0 && i % 5 === 0){
+    console.log("buzz")
+  }
+  else {
+    console.log(i)
+  }
+}

js/grade.js

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+// ### grade.js
+// Write a program that will print the letter grade, given a variable with a test score. Display either "A", "B", "C", "D", or "F", for an score that is an integer between 0 and 100.
+//
+// **Requirements**
+// * Your program should have a variable to store the letter grade (an integer between 0 and 100)
+// * For the letter grades, you may use whatever grading scale you like
+// * You must use a switch statement (hint, you may need to review and think about how the `switch` statement works)
+
+var score = 69
+var gradescale
+
+switch (true) {
+  case (score <= 50):
+    console.log("F");
+    break;
+  case (score <= 60):
+    console.log("D");
+    break;
+  case (score <= 70):
+    console.log("C");
+    break;
+  case (score <= 80):
+    console.log("B");
+    break;
+  case (score <= 100):
+    console.log("A");
+    break;
+
+  }

js/phonebook.js

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+var phoneBook = {
+  "Abe": "111-111-1111",
+  "Bob": "222-222-2222",
+  "Cam": "333-333-3333",
+  "Dan": "444-444-4444",
+  "Ern": "555-555-5555",
+  "Fry": "111-111-1111",
+  "Gil": "222-222-2222",
+  "Hal": "333-333-3333",
+  "Ike": "444-444-4444",
+  "Jim": "555-555-5555",
+  "Kip": "111-111-1111",
+  "Liv": "222-222-2222",
+  "Mia": "333-333-3333",
+  "Nik": "444-444-4444",
+  "Oli": "555-555-5555",
+  "Pam": "111-111-1111",
+  "Qiq": "222-222-2222",
+  "Rob": "333-333-3333",
+  "Stu": "444-444-4444",
+  "Tad": "555-555-5555",
+  "Uwe": "111-111-1111",
+  "Val": "222-222-2222",
+  "Wil": "333-333-3333",
+  "Xiu": "444-444-4444",
+  "Yam": "555-555-5555",
+  "Zed": "111-111-1111"
+};
+
+// for (var contact in phoneBook) {
+//   console.log(phoneBook[contact])
+// }
+
+var freq = 0
+var x
+for (x in phoneBook) {
+  if (phoneBook[x] === "333-333-3333"){
+    console.log(x)
+    freq += 1
+  }
+}
+console.log(freq)

js/reverse.js

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+// ### reverse.js
+// Write a program that will take a hardcoded string, and console log the reversed version of it.
+//
+// **Requirements**
+// * You must use a `for` loop. No `.reverse()`
+// * You may use the string below
+//
+// ```js
+// var inputString = 'building';
+// ```
+//
+// ---
+
+var inputString = 'building'
+var reverseString = []
+
+var inputArray = inputString.split("")
+
+console.log(inputArray)
+
+for (i = 0; i < inputArray.length; i++) {
+  reverseString.push(inputArray[inputArray.length-1-i])
+}
+
+console.log(reverseString.join(""))
+// console.log(inputString.split("").reverse().join(''))