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Elso hazi #14
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Elso hazi #14
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| if tup[-1] == ending: | ||
| res.append(tup) | ||
| return res | ||
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wow :) Klassz megoldas, bar egy kicsit lassu. https://wiki.python.org/moin/HowTo/Sorting
key functions alatt talasz elegansabb megoldast.
basic/list2.py
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| def remove_adjacent(nums): | ||
| # +++your code here+++ | ||
| return | ||
| return list(set(nums)) |
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haat... nem egeszen. mit gondolsz jo eredmenyt kapnal mondjuk [1,2,3,3,1] listara?
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Ja igen elnéztem, azt hittem csak simán halmazként kell visszaadni. Javítom majd:)
basic/list2.py
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| def linear_merge(list1, list2): | ||
| # +++your code here+++ | ||
| return | ||
| return sorted(list1 + list2) |
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nem rossz probalkozas, de a python sorted TimSort algoritmussal dolgozik nlogn idoben. A feladat leirasaban a megoldas; a ket lista eleve rendezett. ;)
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