Assignment-one updations

02_activities/assignments/assignment1.sql

@@ -1,24 +1,23 @@
 /* ASSIGNMENT 1 */
 /* SECTION 2 */
 
-
 --SELECT
 /* 1. Write a query that returns everything in the customer table. */
-
+select * from customer;
 
 
 /* 2. Write a query that displays all of the columns and 10 rows from the cus- tomer table, 
 sorted by customer_last_name, then customer_first_ name. */
-
+select * from customer order by customer_last_name,customer_first_name limit 10;
 
 
 --WHERE
 /* 1. Write a query that returns all customer purchases of product IDs 4 and 9. */
 -- option 1
-
+select * from customer_purchases where product_id = 4 or product_id = 9;
 
 -- option 2
-
+select * from customer_purchases where product_id in ( 4, 9);
 
 
 /*2. Write a query that returns all customer purchases and a new calculated column 'price' (quantity * cost_to_customer_per_qty), 
@@ -27,48 +26,68 @@ filtered by vendor IDs between 8 and 10 (inclusive) using either:
 	2.  one condition using BETWEEN
 */
 -- option 1
-
+select * , (quantity * cost_to_customer_per_qty) as price from customer_purchases where vendor_id >= 8 AND vendor_id <= 10;
 
 -- option 2
 
-
+select * , (quantity * cost_to_customer_per_qty) as price from customer_purchases where vendor_id BETWEEN 8 and 10;
 
 --CASE
 /* 1. Products can be sold by the individual unit or by bulk measures like lbs. or oz. 
 Using the product table, write a query that outputs the product_id and product_name
 columns and add a column called prod_qty_type_condensed that displays the word “unit” 
 if the product_qty_type is “unit,” and otherwise displays the word “bulk.” */
-
+SELECT PRODUCT_ID, PRODUCT_NAME,
+	CASE WHEN product_qty_type = 'unit' then 'unit'
+	else 'bulk'
+	end as prod_qty_type_condensed
+ FROM PRODUCT;
 
 
 /* 2. We want to flag all of the different types of pepper products that are sold at the market. 
 add a column to the previous query called pepper_flag that outputs a 1 if the product_name 
 contains the word “pepper” (regardless of capitalization), and otherwise outputs 0. */
-
+SELECT PRODUCT_ID, PRODUCT_NAME,
+	CASE WHEN product_qty_type = 'unit' then 'unit'
+	else 'bulk'
+	end as prod_qty_type_condensed,
+	case when product_name like '%pepper%' then 1
+	else 0 
+	end as pepper_flag
+ FROM PRODUCT;
 
 
 --JOIN
 /* 1. Write a query that INNER JOINs the vendor table to the vendor_booth_assignments table on the 
 vendor_id field they both have in common, and sorts the result by vendor_name, then market_date. */
 
-
-
+select v.vendor_id, v.vendor_name,v.vendor_type, v.vendor_owner_first_name, v.vendor_owner_last_name ,vb.booth_number
+,vb.market_Date from vendor v inner join vendor_booth_assignments vb
+on v.vendor_id = vb.vendor_id
+order by v.vendor_name, vb.market_Date;
 
 /* SECTION 3 */
 
 -- AGGREGATE
 /* 1. Write a query that determines how many times each vendor has rented a booth 
 at the farmer’s market by counting the vendor booth assignments per vendor_id. */
 
-
+select v.vendor_id,v.vendor_name,count(vb.booth_number)
+from vendor v inner join vendor_booth_assignments vb
+on v.vendor_id = vb.vendor_id
+group by v.vendor_id,v.vendor_name ;
 
 /* 2. The Farmer’s Market Customer Appreciation Committee wants to give a bumper 
 sticker to everyone who has ever spent more than $2000 at the market. Write a query that generates a list 
 of customers for them to give stickers to, sorted by last name, then first name. 
 
 HINT: This query requires you to join two tables, use an aggregate function, and use the HAVING keyword. */
 
-
+select c.customer_first_name,c.customer_last_name , sum(quantity * cost_to_customer_per_qty) as money_spent from customer c 
+inner join customer_purchases cp on c.customer_id = cp.customer_id
+group by c.customer_first_name, c.customer_last_name
+having money_spent > 2000
+order by c.customer_last_name, c.customer_first_name;
 
 --Temp Table
 /* 1. Insert the original vendor table into a temp.new_vendor and then add a 10th vendor: 
@@ -81,7 +100,13 @@ When inserting the new vendor, you need to appropriately align the columns to be
 -> To insert the new row use VALUES, specifying the value you want for each column:
 VALUES(col1,col2,col3,col4,col5) 
 */
+drop table if exists temp.new_vendor;
+--make the TABLE
+CREATE TEMP TABLE temp.new_vendor AS
+--definition of the table 
+SELECT * FROM vendor;
 
+insert into temp.new_vendor values (10, 'Thomas Superfood Store', 'Fresh Focused' ,'Thomas', 'Rosenthal');
 
 
 -- Date
@@ -90,11 +115,13 @@ VALUES(col1,col2,col3,col4,col5)
 HINT: you might need to search for strfrtime modifers sqlite on the web to know what the modifers for month 
 and year are! */
 
-
+select customer_id, strftime('%m', market_date) as month , strftime( '%Y', market_Date) as year , market_Date from customer_purchases;
 
 /* 2. Using the previous query as a base, determine how much money each customer spent in April 2022. 
 Remember that money spent is quantity*cost_to_customer_per_qty. 
 
 HINTS: you will need to AGGREGATE, GROUP BY, and filter...
 but remember, STRFTIME returns a STRING for your WHERE statement!! */
 
+select customer_id, strftime('%m', market_date) as month , strftime( '%Y', market_Date) as year , sum(quantity * cost_to_Customer_per_qty) as money_spent from customer_purchases
+where month = '04' and year= '2022' group by customer_id;