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Original file line number Diff line number Diff line change
@@ -0,0 +1,14 @@
# [Miscellaneous: Flipping bits](https://www.hackerrank.com/challenges/flipping-bits)

- Difficulty: `#easy`
- Category: `#ProblemSolvingBasic` `#BitManipulation`

## Using bitwise operations

The bitwise NOT operator (~) flips all bits of the number.

The & 0xFFFFFFFF ensures that we only keep the last 32 bits,
effectively simulating a 32-bit unsigned integer.

This is a more efficient and concise way to achieve the same result
as the original code, without needing to convert to binary strings.
Original file line number Diff line number Diff line change
@@ -0,0 +1,7 @@
# pylint: disable=line-too-long
# @link Problem definition [[docs/hackerrank/interview_preparation_kit/miscellaneous/flipping-bits.md]] # noqa
# @see Solution Notes: [[docs/hackerrank/interview_preparation_kit/miscellaneous/flipping-bits-alt-solution-notes.md]] # noqa
# pylint: enable=line-too-long

def flippingBitsAlt(number: int) -> int:
return ~number & 0xFFFFFFFF
Original file line number Diff line number Diff line change
Expand Up @@ -3,6 +3,7 @@

from ....lib.loader import loadTestCases
from .flipping_bits import flippingBits
from .flipping_bits_alt import flippingBitsAlt

FILE_PATH = str(Path(__file__).resolve().parent)

Expand All @@ -22,3 +23,8 @@ def test_flipping_bits(self):
flippingBits(_tt['input']), _tt['answer'],
f"{_} | flippingBits({_tt['input']}) must be "
f"=> {_tt['answer']}")

self.assertEqual(
flippingBitsAlt(_tt['input']), _tt['answer'],
f"{_} | flippingBitsAlt({_tt['input']}) must be "
f"=> {_tt['answer']}")
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