completed the assignment and add image to image file

02_activities/assignments/DC_Cohort/Assignment1.md

@@ -108,6 +108,8 @@ Please do not pick the exact same tables that I have already diagrammed. For exa
 
 ***
 
+
+
 ## Section 2:
 You can start this section following *session 2*.
 
@@ -205,5 +207,5 @@ Consider, for example, concepts of fariness, inequality, social structures, marg
 
 
 ```
-Your thoughts...
+One random example that I can think about that might be embedded within something as small as sinks and paper towel machines is their ability to detect skin tones. This is something I notice almost every day in the office and why I am even very passionate about equity-oriented design because with a lot of tools in society they are designed based on white skin, so when people who have darker skin tones try to use these devices they end up not working for us. While this might seem like a small problem when it comes to sinks and paper towel machines but this problem cascades when we start to this about facial recognition devices, pulse oximeters, and other technologies and tools that have deep rooted algorithmic biases embedded within their databases. 
 ```

02_activities/assignments/DC_Cohort/assignment1.sql

@@ -4,17 +4,23 @@
 
 --SELECT
 /* 1. Write a query that returns everything in the customer table. */
-
+SELECT *
+FROM  customer;
 
 
 /* 2. Write a query that displays all of the columns and 10 rows from the cus- tomer table, 
 sorted by customer_last_name, then customer_first_ name. */
-
-
+SELECT *
+FROM customer
+ORDER BY customer_last_name, customer_first_name
+LIMIT 10;
 
 --WHERE
 /* 1. Write a query that returns all customer purchases of product IDs 4 and 9. */
-
+SELECT *
+FROM customer_purchases
+WHERE product_id = 4
+OR product_id = 9;
 
 
 /*2. Write a query that returns all customer purchases and a new calculated column 'price' (quantity * cost_to_customer_per_qty), 
@@ -23,30 +29,66 @@ filtered by customer IDs between 8 and 10 (inclusive) using either:
 	2.  one condition using BETWEEN
 */
 -- option 1
+SELECT *, (quantity*cost_to_customer_per_qty) as 'price'
+FROM customer_purchases
 
+WHERE customer_id = 8 
+AND 10;
 
--- option 2
 
+-- option 2
+SELECT *, (quantity*cost_to_customer_per_qty) as 'price'
+FROM customer_purchases
 
+WHERE customer_id BETWEEN 8 AND 10;
 
 --CASE
 /* 1. Products can be sold by the individual unit or by bulk measures like lbs. or oz. 
 Using the product table, write a query that outputs the product_id and product_name
 columns and add a column called prod_qty_type_condensed that displays the word “unit” 
 if the product_qty_type is “unit,” and otherwise displays the word “bulk.” */
 
+SELECT *
+,CASE WHEN product_qty_type  =  'unit'  
+THEN 'unit'
+ELSE  'bulk'
+END AS product_qty_type_condensed
 
+FROM product;
 
 /* 2. We want to flag all of the different types of pepper products that are sold at the market. 
 add a column to the previous query called pepper_flag that outputs a 1 if the product_name 
 contains the word “pepper” (regardless of capitalization), and otherwise outputs 0. */
 
+SELECT *
+,CASE WHEN product_qty_type  =  'unit'  
+THEN 'unit'
+ELSE  'bulk'
+END AS product_qty_type_condensed
+
+,CASE WHEN product_name LIKE '%pepper%'
+	THEN '1'
+	ELSE '0'
+	END as pepper_flag
+
+	FROM product;
 
 
 --JOIN
 /* 1. Write a query that INNER JOINs the vendor table to the vendor_booth_assignments table on the 
 vendor_id field they both have in common, and sorts the result by vendor_name, then market_date. */
 
+SELECT DISTINCT vendor_name,
+market_date,
+vb.vendor_id,
+v.vendor_id
+
+FROM vendor as v
+INNER JOIN vendor_booth_assignments as vb
+	ON vb.vendor_id = v.vendor_id
+
+ORDER BY vendor_name;
+
 
 
 
@@ -56,6 +98,9 @@ vendor_id field they both have in common, and sorts the result by vendor_name, t
 /* 1. Write a query that determines how many times each vendor has rented a booth 
 at the farmer’s market by counting the vendor booth assignments per vendor_id. */
 
+SELECT vendor_id, COUNT(vendor_id) as num_of_rented_booths
+FROM vendor_booth_assignments
+GROUP BY vendor_id;
 
 
 /* 2. The Farmer’s Market Customer Appreciation Committee wants to give a bumper 
@@ -64,6 +109,19 @@ of customers for them to give stickers to, sorted by last name, then first name.
 
 HINT: This query requires you to join two tables, use an aggregate function, and use the HAVING keyword. */
 
+SELECT 
+    customer_first_name,
+    customer_last_name,
+    SUM(quantity*cost_to_customer_per_qty) AS total_spent
+
+FROM customer_purchases AS cp
+INNER JOIN customer AS c
+    ON cp.customer_id = c.customer_id
+
+	GROUP BY customer_first_name, customer_last_name
+
+	HAVING  SUM(quantity*cost_to_customer_per_qty) > 2000
+ORDER BY customer_last_name, customer_first_name;
 
 
 --Temp Table
@@ -78,7 +136,17 @@ When inserting the new vendor, you need to appropriately align the columns to be
 VALUES(col1,col2,col3,col4,col5) 
 */
 
+DROP TABLE IF EXISTS temp.new_vendor;
+
+CREATE TABLE temp.new_vendor AS
+SELECT *
+FROM  vendor;
+
+INSERT INTO new_vendor (vendor_id, vendor_name, vendor_type, vendor_owner_first_name, vendor_owner_last_name)
+VALUES (10, 'Thomass Superfood Store', 'Fresh Focused', 'Thomas', 'Rosenthal');
 
+SELECT *
+FROM  temp.new_vendor
 
 -- Date
 /*1. Get the customer_id, month, and year (in separate columns) of every purchase in the customer_purchases table.