Solution

[YuriiPanki]

No description provided.

[mateacademy-ai-mentor]

Review Summary

Excellent work! Your function correctly counts the occurrences of the letter in a case-insensitive manner and meets all the core requirements of the task. I am approving your solution.

For future reference, while your loop-based approach is perfectly functional, a more idiomatic and concise Python solution could be achieved using built-in string methods. Consider how you could use phrase.lower().count(letter.lower()) to solve the problem in a single line. This is a common pattern in Python that is good to be familiar with.

Keep up the great effort!

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