Solution #3146
Solution #3146
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Review Summary
Great job on the core logic! Your function correctly performs a case-insensitive count. However, I'm requesting a couple of changes to align with the task requirements. The function is missing the required docstring, which is a specific requirement from the task description. Additionally, while your loop-based approach works, the guidelines recommend using Python's built-in string methods like .lower() and .count() for a more concise and idiomatic solution. Please make these adjustments to complete the task.
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Footnotes
app/main.py
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| def count_occurrences(phrase: str, letter: str) -> int: | ||
| # write your code here | ||
| pass | ||
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The function is missing the required docstring. Please add the docstring provided in the task description to explain what the function does, its parameters, and what it returns.
app/main.py
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| for character in phrase: | ||
| if character.lower() == letter.lower(): | ||
| counter += 1 | ||
| return counter |
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While this loop correctly counts the occurrences, the task guidelines recommend a more Pythonic approach. Consider using the built-in lower() and count() string methods to achieve the same result in a single line without an explicit loop.
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