Assignment One

02_activities/assignments/Cohort_8/assignment1.sql

@@ -4,17 +4,25 @@
 
 --SELECT
 /* 1. Write a query that returns everything in the customer table. */
-
+SELECT *
+FROM customer;
 
 
 /* 2. Write a query that displays all of the columns and 10 rows from the cus- tomer table, 
 sorted by customer_last_name, then customer_first_ name. */
+SELECT * 
+FROM customer
+ORDER BY customer_last_name, customer_first_name 
+LIMIT 10;
 
 
 
 --WHERE
 /* 1. Write a query that returns all customer purchases of product IDs 4 and 9. */
-
+SELECT *
+FROM customer_purchases
+WHERE product_id in (4,9);
+
 
 
 /*2. Write a query that returns all customer purchases and a new calculated column 'price' (quantity * cost_to_customer_per_qty), 
@@ -24,9 +32,18 @@ filtered by customer IDs between 8 and 10 (inclusive) using either:
 */
 -- option 1
 
+SELECT *, 
+	(quantity * cost_to_customer_per_qty) as price
+FROM customer_purchases
+WHERE customer_id >= 8
+	AND customer_id <= 10;
 
 -- option 2
 
+SELECT *, 
+	(quantity * cost_to_customer_per_qty) as price
+FROM customer_purchases
+WHERE customer_id BETWEEN 8 and 10;
 
 
 --CASE
@@ -35,18 +52,41 @@ Using the product table, write a query that outputs the product_id and product_n
 columns and add a column called prod_qty_type_condensed that displays the word “unit” 
 if the product_qty_type is “unit,” and otherwise displays the word “bulk.” */
 
+SELECT 
+	product_id,
+	product_name, 
+	CASE 
+		WHEN product_qty_type = 'unit' THEN 'unit' 
+		ELSE 'bulk' 
+	END as prod_qty_type_condensed
+FROM product;
 
 
 /* 2. We want to flag all of the different types of pepper products that are sold at the market. 
 add a column to the previous query called pepper_flag that outputs a 1 if the product_name 
 contains the word “pepper” (regardless of capitalization), and otherwise outputs 0. */
 
+SELECT 
+	product_id,
+	product_name, 
+	CASE 
+		WHEN product_qty_type = 'unit' THEN 'unit' 
+		ELSE 'bulk' 
+	END as prod_qty_type_condensed,
+	CASE 
+		WHEN product_name like '%pepper%' THEN 1 
+		ELSE 0 
+	END as pepper_flag
+FROM product;
 
 
 --JOIN
 /* 1. Write a query that INNER JOINs the vendor table to the vendor_booth_assignments table on the 
 vendor_id field they both have in common, and sorts the result by vendor_name, then market_date. */
 
+SELECT *
+FROM vendor INNER JOIN vendor_booth_assignments on vendor.vendor_id = vendor_booth_assignments.vendor_id
+ORDER BY vendor_name, market_date;
 
 
 
@@ -56,6 +96,9 @@ vendor_id field they both have in common, and sorts the result by vendor_name, t
 /* 1. Write a query that determines how many times each vendor has rented a booth 
 at the farmer’s market by counting the vendor booth assignments per vendor_id. */
 
+SELECT vendor_id, count(*)
+FROM vendor_booth_assignments
+GROUP BY vendor_id;
 
 
 /* 2. The Farmer’s Market Customer Appreciation Committee wants to give a bumper 
@@ -64,6 +107,16 @@ of customers for them to give stickers to, sorted by last name, then first name.
 
 HINT: This query requires you to join two tables, use an aggregate function, and use the HAVING keyword. */
 
+SELECT 
+	customer.customer_id,
+	customer_last_name,
+	customer_first_name,
+	SUM(quantity*cost_to_customer_per_qty) as total_spend
+FROM customer_purchases inner join customer on customer_purchases.customer_id = customer.customer_id
+GROUP BY customer.customer_id
+HAVING total_spend >= 2000
+ORDER BY customer_last_name, customer_first_name;
+
 
 
 --Temp Table
@@ -77,6 +130,16 @@ When inserting the new vendor, you need to appropriately align the columns to be
 -> To insert the new row use VALUES, specifying the value you want for each column:
 VALUES(col1,col2,col3,col4,col5) 
 */
+DROP TABLE IF EXISTS temp.new_vendor;
+
+CREATE TABLE temp.new_vendor AS 
+SELECT*
+FROM vendor;
+
+INSERT into temp.new_vendor (vendor_id, vendor_name, vendor_type, vendor_owner_first_name, vendor_owner_last_name)
+VALUES (10, 'Thomass Superfood Store', 'Fresh Focused', 'Thomas', 'Rosenthal');
+
+SELECT * FROM new_vendor;