Skip to content
Open
Show file tree
Hide file tree
Changes from 2 commits
Commits
File filter

Filter by extension

Filter by extension

Conversations
Failed to load comments.
Loading
Jump to
Jump to file
Failed to load files.
Loading
Diff view
Diff view
21 changes: 21 additions & 0 deletions 02_activities/assignments/Assignment2.md
Original file line number Diff line number Diff line change
Expand Up @@ -55,6 +55,27 @@ The store wants to keep customer addresses. Propose two architectures for the CU

```
Your answer...

Option 1 – Overwrite

One record per customer in CUSTOMER_ADDRESS.

When a customer changes their address, the row is updated with the new information.

No history of previous addresses is kept.

This is Type 1 Slowly Changing Dimension

Option 2 – Retain Changes (History)

Multiple records per customer in CUSTOMER_ADDRESS.

Each address has start_date and end_date columns.

When a customer moves, a new record is inserted with the new address, and the old record is marked inactive by setting end_date.

This is Type 2 Slowly Changing Dimension.

```

***
Expand Down

Choose a reason for hiding this comment

The reason will be displayed to describe this comment to others. Learn more.

Please indicate the relationships among tables

Copy link
Owner Author

Choose a reason for hiding this comment

The reason will be displayed to describe this comment to others. Learn more.

sorry, what do you mean relationship among tables?
I have indicated PK, FK in all tables and connected related tables.
Thanks.

Choose a reason for hiding this comment

The reason will be displayed to describe this comment to others. Learn more.

relationship here mean 1 to many relationship or many to many relationship or....
you may indicate the relationship by simple or putting "1" or "many" beside the key

Copy link
Owner Author

Choose a reason for hiding this comment

The reason will be displayed to describe this comment to others. Learn more.

new file is added to address your comment.
Thank you

Copy link
Owner Author

Choose a reason for hiding this comment

The reason will be displayed to describe this comment to others. Learn more.

@monzchan
Hi
Could you please confirm that my assignments (1&2) is considered as complete. I haven't yet received any feedback on this.
Thank you.

Loading
Sorry, something went wrong. Reload?
Sorry, we cannot display this file.
Sorry, this file is invalid so it cannot be displayed.
155 changes: 154 additions & 1 deletion 02_activities/assignments/assignment2.sql
Original file line number Diff line number Diff line change
Expand Up @@ -19,6 +19,12 @@ HINT: keep the syntax the same, but edited the correct components with the strin
The `||` values concatenate the columns into strings.
Edit the appropriate columns -- you're making two edits -- and the NULL rows will be fixed.
All the other rows will remain the same.) */
SELECT
product_name || ', ' || COALESCE(product_size,'') || ' (' || COALESCE(product_qty_type,'') || ')'
FROM product;
SELECT
product_name || ', ' || COALESCE(product_size,'unit') || ' (' || COALESCE(product_qty_type,'unit') || ')'
FROM product;



Expand All @@ -32,17 +38,41 @@ each new market date for each customer, or select only the unique market dates p
(without purchase details) and number those visits.
HINT: One of these approaches uses ROW_NUMBER() and one uses DENSE_RANK(). */

SELECT
customer_id,
market_date,
ROW_NUMBER() OVER(PARTITION BY customer_id ORDER BY market_date) AS visit_number
FROM customer_purchases;


/* 2. Reverse the numbering of the query from a part so each customer’s most recent visit is labeled 1,
then write another query that uses this one as a subquery (or temp table) and filters the results to
only the customer’s most recent visit. */

SELECT *
FROM (
SELECT
customer_id,
market_date,
ROW_NUMBER() OVER(PARTITION BY customer_id ORDER BY market_date DESC) AS visit_number
FROM customer_purchases
) sub
WHERE visit_number = 1;




/* 3. Using a COUNT() window function, include a value along with each row of the
customer_purchases table that indicates how many different times that customer has purchased that product_id. */

SELECT
customer_id,
product_id,
market_date,
quantity,
cost_to_customer_per_qty,
COUNT(*) OVER(PARTITION BY customer_id, product_id) AS times_purchased
FROM customer_purchases;


-- String manipulations
Expand All @@ -57,10 +87,24 @@ Remove any trailing or leading whitespaces. Don't just use a case statement for

Hint: you might need to use INSTR(product_name,'-') to find the hyphens. INSTR will help split the column. */

SELECT
product_name,

TRIM(
SUBSTR(
product_name,
INSTR(product_name,'-') + 1
)
) AS description
FROM product
WHERE INSTR(product_name,'-') > 0;


/* 2. Filter the query to show any product_size value that contain a number with REGEXP. */

SELECT *
FROM product
WHERE product_size REGEXP '[0-9]';


-- UNION
Expand All @@ -73,6 +117,36 @@ HINT: There are a possibly a few ways to do this query, but if you're struggling
3) Query the second temp table twice, once for the best day, once for the worst day,
with a UNION binding them. */

--Aggregate total sales per date
WITH sales_per_day AS (
SELECT
market_date,
SUM(quantity * cost_to_customer_per_qty) AS total_sales
FROM customer_purchases
GROUP BY market_date
)

--Rank the dates by total sales
, ranked_sales AS (
SELECT
market_date,
total_sales,
RANK() OVER(ORDER BY total_sales DESC) AS rank_high, -- highest sales
RANK() OVER(ORDER BY total_sales ASC) AS rank_low -- lowest sales
FROM sales_per_day
)

--Select best and worst days
SELECT 'Best Day' AS label, market_date, total_sales
FROM ranked_sales
WHERE rank_high = 1

UNION

SELECT 'Worst Day' AS label, market_date, total_sales
FROM ranked_sales
WHERE rank_low = 1;




Expand All @@ -89,6 +163,26 @@ Think a bit about the row counts: how many distinct vendors, product names are t
How many customers are there (y).
Before your final group by you should have the product of those two queries (x*y). */

SELECT
v.vendor_name,
p.product_name,
SUM(5 * vi.original_price) AS potential_revenue
FROM
(SELECT DISTINCT vendor_id, vendor_name FROM vendor) v
CROSS JOIN
(SELECT DISTINCT customer_id FROM customer) c
JOIN
vendor_inventory vi
ON vi.vendor_id = v.vendor_id
JOIN
product p
ON p.product_id = vi.product_id
GROUP BY
v.vendor_name,
p.product_name
ORDER BY
v.vendor_name,
p.product_name;


-- INSERT
Expand All @@ -98,17 +192,50 @@ It should use all of the columns from the product table, as well as a new column
Name the timestamp column `snapshot_timestamp`. */


DROP TABLE IF EXISTS product_units;

CREATE TABLE product_units AS
SELECT
*,
CURRENT_TIMESTAMP AS snapshot_timestamp
FROM product
WHERE product_qty_type = 'unit';

SELECT * FROM product_units;






/*2. Using `INSERT`, add a new row to the product_units table (with an updated timestamp).
This can be any product you desire (e.g. add another record for Apple Pie). */

INSERT INTO product_units (product_id, product_name, product_size, product_category_id, product_qty_type, snapshot_timestamp)
VALUES (
1000, -- new product_id
'Apple Pie', -- product_name
'1 unit', -- product_size
100, --product_category_id
'unit', -- product_qty_type
CURRENT_TIMESTAMP -- snapshot_timestamp
);

--SELECT * FROM product_units
--WHERE product_id = 1000;

-- DELETE
/* 1. Delete the older record for the whatever product you added.

HINT: If you don't specify a WHERE clause, you are going to have a bad time.*/

DELETE FROM product_units
WHERE product_name = 'Apple Pie'
AND snapshot_timestamp < (
SELECT MAX(snapshot_timestamp)
FROM product_units
WHERE product_name = 'Apple Pie'
);


-- UPDATE
Expand All @@ -128,6 +255,32 @@ Finally, make sure you have a WHERE statement to update the right row,
you'll need to use product_units.product_id to refer to the correct row within the product_units table.
When you have all of these components, you can run the update statement. */


ALTER TABLE product_units
ADD COLUMN current_quantity INT;

SELECT vi.product_id, vi.quantity
FROM vendor_inventory vi
INNER JOIN (
SELECT product_id, MAX(market_date) AS last_date
FROM vendor_inventory
GROUP BY product_id
) latest
ON vi.product_id = latest.product_id AND vi.market_date = latest.last_date;


UPDATE product_units
SET current_quantity = COALESCE((
SELECT vi.quantity
FROM vendor_inventory vi
INNER JOIN (
SELECT product_id, MAX(market_date) AS last_date
FROM vendor_inventory
GROUP BY product_id
) latest
ON vi.product_id = latest.product_id AND vi.market_date = latest.last_date
WHERE vi.product_id = product_units.product_id
), 0);

SELECT * FROM product_units