SQL Assignment2

02_activities/assignments/Cohort_8/assignment1.sql → 02_activities/assignments/Cohort_8/assignment1/assignment1.sql

@@ -4,17 +4,22 @@
 
 --SELECT
 /* 1. Write a query that returns everything in the customer table. */
-
+SELECT * FROM customer;
 
 
 /* 2. Write a query that displays all of the columns and 10 rows from the cus- tomer table, 
 sorted by customer_last_name, then customer_first_ name. */
-
+SELECT *
+FROM customer
+ORDER BY customer_last_name, customer_first_name
+LIMIT 10;
 
 
 --WHERE
 /* 1. Write a query that returns all customer purchases of product IDs 4 and 9. */
-
+SELECT *
+FROM purchases
+WHERE product_id IN (4, 9);
 
 
 /*2. Write a query that returns all customer purchases and a new calculated column 'price' (quantity * cost_to_customer_per_qty), 
@@ -23,30 +28,55 @@ filtered by customer IDs between 8 and 10 (inclusive) using either:
 	2.  one condition using BETWEEN
 */
 -- option 1
-
+	SELECT *,
+       (quantity * cost_to_customer_per_qty) AS price
+FROM customer_purchases
+WHERE customer_id >= 8
+  AND customer_id <= 10;
 
 -- option 2
-
+SELECT *,
+       (quantity * cost_to_customer_per_qty) AS price
+FROM customer_purchases
+WHERE customer_id BETWEEN 8 AND 10;
 
 
 --CASE
 /* 1. Products can be sold by the individual unit or by bulk measures like lbs. or oz. 
 Using the product table, write a query that outputs the product_id and product_name
 columns and add a column called prod_qty_type_condensed that displays the word “unit” 
 if the product_qty_type is “unit,” and otherwise displays the word “bulk.” */
-
+SELECT 
+    product_id,
+    product_name,
+    CASE 
+        WHEN product_qty_type = 'unit' THEN 'unit'
+        ELSE 'bulk'
+    END AS prod_qty_type_condensed
+FROM product;
 
 
 /* 2. We want to flag all of the different types of pepper products that are sold at the market. 
 add a column to the previous query called pepper_flag that outputs a 1 if the product_name 
 contains the word “pepper” (regardless of capitalization), and otherwise outputs 0. */
-
+SELECT *,
+       (quantity * cost_to_customer_per_qty) AS price,
+       CASE 
+           WHEN LOWER(product_name) LIKE '%pepper%' THEN 1
+           ELSE 0
+       END AS pepper_flag
+FROM customer_purchases
+WHERE customer_id BETWEEN 8 AND 10;
 
 
 --JOIN
 /* 1. Write a query that INNER JOINs the vendor table to the vendor_booth_assignments table on the 
 vendor_id field they both have in common, and sorts the result by vendor_name, then market_date. */
-
+SELECT *
+FROM vendor v
+INNER JOIN vendor_booth_assignments vba
+    ON v.vendor_id = vba.vendor_id
+ORDER BY v.vendor_name, vba.market_date;
 
 
 
@@ -55,15 +85,34 @@ vendor_id field they both have in common, and sorts the result by vendor_name, t
 -- AGGREGATE
 /* 1. Write a query that determines how many times each vendor has rented a booth 
 at the farmer’s market by counting the vendor booth assignments per vendor_id. */
-
+SELECT 
+    vendor_id,
+    COUNT(*) AS booth_rental_count
+FROM vendor_booth_assignments
+GROUP BY vendor_id;
 
 
 /* 2. The Farmer’s Market Customer Appreciation Committee wants to give a bumper 
 sticker to everyone who has ever spent more than $2000 at the market. Write a query that generates a list 
 of customers for them to give stickers to, sorted by last name, then first name. 
 
 HINT: This query requires you to join two tables, use an aggregate function, and use the HAVING keyword. */
-
+SELECT 
+    c.customer_id,
+    c.customer_last_name,
+    c.customer_first_name,
+    SUM(p.quantity * p.cost_to_customer_per_qty) AS total_spent
+FROM customer c
+JOIN customer_purchases p
+    ON c.customer_id = p.customer_id
+GROUP BY 
+    c.customer_id,
+    c.customer_last_name,
+    c.customer_first_name
+HAVING SUM(p.quantity * p.cost_to_customer_per_qty) > 2000
+ORDER BY 
+    c.customer_last_name,
+    c.customer_first_name;
 
 
 --Temp Table
@@ -77,20 +126,35 @@ When inserting the new vendor, you need to appropriately align the columns to be
 -> To insert the new row use VALUES, specifying the value you want for each column:
 VALUES(col1,col2,col3,col4,col5) 
 */
+CREATE TEMP TABLE temp.new_vendor AS
+SELECT *
+FROM vendor;
 
+INSERT INTO temp.new_vendor (vendor_id, vendor_name, vendor_type, vendor_description)
+VALUES (10, 'Thomass Superfood Store', 'Fresh Focused', 'Owner: Thomas Rosenthal');
 
 
 -- Date
 /*1. Get the customer_id, month, and year (in separate columns) of every purchase in the customer_purchases table.
 
 HINT: you might need to search for strfrtime modifers sqlite on the web to know what the modifers for month 
 and year are! */
-
+SELECT 
+    customer_id,
+    STRFTIME('%m', purchase_date) AS purchase_month,
+    STRFTIME('%Y', purchase_date) AS purchase_year
+FROM customer_purchases;
 
 
 /* 2. Using the previous query as a base, determine how much money each customer spent in April 2022. 
 Remember that money spent is quantity*cost_to_customer_per_qty. 
 
 HINTS: you will need to AGGREGATE, GROUP BY, and filter...
 but remember, STRFTIME returns a STRING for your WHERE statement!! */
-
+SELECT 
+    customer_id,
+    SUM(quantity * cost_to_customer_per_qty) AS total_spent
+FROM customer_purchases
+WHERE STRFTIME('%m', purchase_date) = '04'
+  AND STRFTIME('%Y', purchase_date) = '2022'
+GROUP BY customer_id;