Add print message before calling llm async_execute_model_call method

expectedparrot · Jan 17, 2025 · 090e8a1 · 090e8a1
1 parent 4013d70
commit 090e8a1
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Showing 2 changed files with 5 additions and 2 deletions.
diff --git a/edsl/jobs/Jobs.py b/edsl/jobs/Jobs.py
@@ -515,6 +515,7 @@ async def _execute_with_remote_cache(self, run_job_async: bool) -> Results:
         #     remote_cache_description=self.run_config.parameters.remote_cache_description,
         # ):
         runner = JobsRunnerAsyncio(self, environment=self.run_config.environment)
+        run_job_async = True
         if run_job_async:
             results = await runner.run_async(self.run_config.parameters)
         else:

diff --git a/edsl/language_models/LanguageModel.py b/edsl/language_models/LanguageModel.py
@@ -394,7 +394,10 @@ async def _async_get_intended_model_call_outcome(
             from edsl.config import CONFIG
 
             TIMEOUT = float(CONFIG.get("EDSL_API_TIMEOUT"))
-
+            print("#######DEBUG############")
+            print(
+                "Calling model to answer question prompt:\n" + user_prompt, flush=True
+            )
             response = await asyncio.wait_for(f(**params), timeout=TIMEOUT)
             new_cache_key = cache.store(
                 **cache_call_params, response=response
@@ -571,7 +574,6 @@ def example(
             return Model(skip_api_key_check=True)
 
     def from_cache(self, cache: "Cache") -> LanguageModel:
-
         from copy import deepcopy
         from types import MethodType
         from edsl import Cache