Create KeithNumber.java

C/Bubble_Sort.c

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+// Bubble sort in C
+
+#include <stdio.h>
+
+// perform the bubble sort
+void bubbleSort(int array[], int size) {
+
+  // loop to access each array element
+  for (int step = 0; step < size - 1; ++step) {
+
+    // loop to compare array elements
+    for (int i = 0; i < size - step - 1; ++i) {
+
+      // compare two adjacent elements
+      // change > to < to sort in descending order
+      if (array[i] > array[i + 1]) {
+
+        // swapping occurs if elements
+        // are not in the intended order
+        int temp = array[i];
+        array[i] = array[i + 1];
+        array[i + 1] = temp;
+      }
+    }
+  }
+}
+
+// print array
+void printArray(int array[], int size) {
+  for (int i = 0; i < size; ++i) {
+    printf("%d  ", array[i]);
+  }
+  printf("\n");
+}
+
+int main() {
+  int data[] = {-2, 45, 0, 11, -9};
+
+  // find the array's length
+  int size = sizeof(data) / sizeof(data[0]);
+
+  bubbleSort(data, size);
+
+  printf("Sorted Array in Ascending Order:\n");
+  printArray(data, size);
+}

java/KeithNumber.java

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+import java.util.*;  
+class KeithNumberExample1  
+{  
+//user-defined function that checks if the given number is Keith or not  
+static boolean isKeith(int x)  
+{  
+//List stores all the digits of the X  
+ArrayList<Integer> terms=new ArrayList<Integer>();  
+//n denotes the number of digits   
+int temp = x, n = 0;   
+//executes until the condition becomes false  
+while (temp > 0)  
+{  
+//determines the last digit of the number and add it to the List      
+terms.add(temp%10);  
+//removes the last digit  
+temp = temp/10;  
+//increments the number of digits (n) by 1  
+n++;  
+}  
+//reverse the List  
+Collections.reverse(terms);  
+int next_term = 0, i = n;  
+//finds next term for the series  
+//loop executes until the condition returns true  
+while (next_term < x)  
+{  
+next_term = 0;  
+//next term is the sum of previous n terms (it depends on number of digits the number has)  
+for (int j=1; j<=n; j++)  
+next_term = next_term + terms.get(i-j);  
+terms.add(next_term);  
+i++;  
+}  
+//when the control comes out of the while loop, there will be two conditions:  
+//either next_term will be equal to x or greater than x  
+//if equal, the given number is Keith, else not  
+return (next_term == x);  
+}  
+//driver code  
+public static void main(String[] args)  
+{  
+//calling the user-defined method inside the if statement and print the result accordingly    
+if (isKeith(19))  
+System.out.println("Yes, the given number is a Keith number.");  
+else  
+System.out.println("No, the given number is not a Keith number.");  
+if(isKeith(742))  
+System.out.println("Yes, the given number is a Keith number.");  
+else  
+System.out.println("No, the given number is not a Keith number.");  
+if(isKeith(4578))  
+System.out.println("Yes, the given number is a Keith number.");  
+else  
+System.out.println("No, the given number is not a Keith number.");  
+}  
+}