Solved lab

lab_4.sql

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+USE sakila;
+
+-- CHALLENGE- Joining on mulitiple tables
+-- 1 - list the number of films per category
+
+SELECT
+c.name AS category_name,
+COUNT(fc.film_id) AS number_of_films
+FROM category AS c
+INNER JOIN film_category AS fc
+ON c.category_id = fc.category_id
+GROUP BY
+c.name;
+
+-- 2 - Retrieve the store ID, city and country for each store
+SELECT
+s.store_id,
+ci.city,
+co.country
+FROM store AS s
+INNER JOIN address AS a
+ON s.address_id = a.address_id
+INNER JOIN city AS ci
+ON a.city_id = ci.city_id
+INNER JOIN country AS co
+ON ci.country_id = co.country_id;
+
+-- 3 - calculate the total revenue generated by each store in dollars
+SELECT
+s.store_id,
+SUM(p.amount) AS total_revenue
+FROM store AS s
+INNER JOIN staff AS st
+ON s.store_id = st.store_id
+INNER JOIN payment AS p
+ON st.staff_id = p.staff_id
+GROUP BY
+ s.store_id;
+
+ -- 4 - Determine the average running time of films for each category
+ SELECT
+ c.name AS category_name,
+ ROUND(AVG(f.length), 2) AS average_running_time
+ FROM category AS c
+ INNER JOIN film_category AS fc
+ ON c.category_id = fc.category_id
+ INNER JOIN  film AS f
+ ON fc.film_id = f.film_id
+ GROUP BY
+ C.NAME;
+
+ -- 5 - Identify the film categories with the longest average running time
+ SELECT
+ c.name AS category_name,
+ ROUND(AVG(f.length), 2) AS average_running_time
+ FROM category AS c
+ INNER JOIN film_category AS fc
+ ON c.category_id = fc.category_id
+ INNER JOIN film AS f
+ ON fc.film_id = f.film_id
+ GROUP BY
+ c.name
+ ORDER BY average_running_time DESC
+ LIMIT 1;
+
+ -- 6 - Display the top 10 most frequently rented movies in descending order
+ SELECT
+ f.title,
+ COUNT(r.rental_id) AS rental_count
+ FROM film AS f
+ INNER JOIN inventory AS i
+ ON f.film_id = i.film_id
+ INNER JOIN rental AS r
+ ON i.inventory_id = r.inventory_id
+ GROUP BY
+ f.title
+ ORDER BY rental_count desc
+ LIMIT 10;
+
+ -- 7 - Determine if "Academy Dinosaur" can be rented from store 1
+ SELECT
+ f.title,
+ i.store_id,
+ COUNT(i.inventory_id) AS copies_available
+ FROM film AS f
+ INNER JOIN inventory AS i
+ ON f.film_id = i.film_id
+ WHERE f.title = 'Academy Dinosaur'
+ AND i.store_id = 1
+ GROUP BY
+ f.title, i.store_id;
+
+ -- 8 - Provide a list of all distinct film titiles
+ SELECT
+ f.title,
+ CASE
+   WHEN i.inventory_id IS NULL THEN 'NOT available'
+   ELSE 'Available'
+   END AS availability_status
+FROM film AS f
+LEFT JOIN inventory AS i
+ON f.film_id = i.film_id;