Added solution for Problem Equal in java

Algorithms/Equal.java

@@ -0,0 +1,76 @@
+import java.io.*;
+import java.math.*;
+import java.security.*;
+import java.text.*;
+import java.util.*;
+import java.util.concurrent.*;
+import java.util.function.*;
+import java.util.regex.*;
+import java.util.stream.*;
+import static java.util.stream.Collectors.joining;
+import static java.util.stream.Collectors.toList;
+
+class Result {
+
+    /*
+     * Complete the 'equal' function below.
+     *
+     * The function is expected to return an INTEGER.
+     * The function accepts INTEGER_ARRAY arr as parameter.
+     */
+
+    public static int equal(List<Integer> arr) {
+    // Write your code here
+    /*The idea is to first find the minimum value in the list, 
+    subtract the same from each element and check the least step required to make
+    the value 0 using 1,2 and 5 (as given in question). 
+
+
+    let this function be called f which takes minimum value min, it is possible that f(min)>f(min-1) or f(min)>f(min-2) 
+    but as the greatest denomination in question is 5 it is certain that f(min)<f(min-5) 
+    so our objective is to check till f(min-4) */
+    ArrayList<Integer> res=new ArrayList<Integer>();
+    //iterating loop only til 4 as f(min) is surely less than f(min-5) as discussed above
+    for(int j=0;j<4;j++){
+        int minval=Collections.min(arr); //minimum value in list
+        minval-=j;
+    int count=0;
+    for(Integer i:arr){
+        count+=(i-minval)/5+((i-minval)%5)/2+((i-minval)%5)%2; // least way to get a number to 0 using denominations 5,2 and 1 as given in ques
+    }
+    res.add(count);
+    }
+    return Collections.min(res); // returning minimum value of the 4 collected values.
+    }
+
+}
+
+public class Solution {
+    public static void main(String[] args) throws IOException {
+        BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(System.in));
+        BufferedWriter bufferedWriter = new BufferedWriter(new FileWriter(System.getenv("OUTPUT_PATH")));
+
+        int t = Integer.parseInt(bufferedReader.readLine().trim());
+
+        IntStream.range(0, t).forEach(tItr -> {
+            try {
+                int n = Integer.parseInt(bufferedReader.readLine().trim());
+
+                List<Integer> arr = Stream.of(bufferedReader.readLine().replaceAll("\\s+$", "").split(" "))
+                    .map(Integer::parseInt)
+                    .collect(toList());
+
+                int result = Result.equal(arr);
+
+                bufferedWriter.write(String.valueOf(result));
+                bufferedWriter.newLine();
+            } catch (IOException ex) {
+                throw new RuntimeException(ex);
+            }
+        });
+
+        bufferedReader.close();
+        bufferedWriter.close();
+    }
+}
+