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23 changes: 23 additions & 0 deletions sql/task1.sql
Original file line number Diff line number Diff line change
@@ -1,14 +1,37 @@
-- Problem 1: Retrieve all products in the Sports category
-- Write an SQL query to retrieve all products in a specific category.
-- Utilize category ID to select desired products listed within the category
-- Category ID may be changed to better suit search parameters
SELECT *
FROM Products
WHERE Products.category_id = 8;

-- Problem 2: Retrieve the total number of orders for each user
-- Write an SQL query to retrieve the total number of orders for each user.
-- The result should include the user ID, username, and the total number of orders.

SELECT Users.user_id, Users.username, COUNT(Order.order_id) AS total_orders
FROM Users
LEFT JOIN Orders ON Users.user_id = Orders.user_id
GROUP BY Users.user_id, Users.username;


-- Problem 3: Retrieve the average rating for each product
-- Write an SQL query to retrieve the average rating for each product.
-- The result should include the product ID, product name, and the average rating.

SELECT Products.product_id, Products.product_name, AVG(Reviews.rating) AS average_rating
FROM Products
LEFT JOIN Reviews ON Products.product_id = Reviews.product_id
GROUP BY Products.product_id, Products.product_name;

-- Problem 4: Retrieve the top 5 users with the highest total amount spent on orders
-- Write an SQL query to retrieve the top 5 users with the highest total amount spent on orders.
-- The result should include the user ID, username, and the total amount spent.

SELECT Users.user_id, Users.username, SUM(Orders.total_amount) AS total_amount_spent
FROM Users
JOIN Orders ON Users.user_id = Orders.user_id
GROUP BY Users.user_id, Users.username
ORDER BY total_amount_spent DESC
LIMIT 5;
25 changes: 24 additions & 1 deletion sql/task2.sql
Original file line number Diff line number Diff line change
Expand Up @@ -3,17 +3,40 @@
-- The result should include the product ID, product name, and the average rating.
-- Hint: You may need to use subqueries or common table expressions (CTEs) to solve this problem.

SELECT Products.product_id, Products.product_name, Reviews.rating AS average_rating
FROM Products
LEFT JOIN Reviews ON Reviews.product_id = Products.product_id
WHERE Reviews.rating = (SELECT MAX(average_rating)
FROM (SELECT Products.product_id, Products.product_name, AVG(Reviews.rating) AS average_rating
FROM Products
LEFT JOIN Reviews ON Products.product_id = Reviews.product_id
GROUP BY Products.product_id, Products.product_name));

-- Problem 6: Retrieve the users who have made at least one order in each category
-- Write an SQL query to retrieve the users who have made at least one order in each category.
-- The result should include the user ID and username.
-- Hint: You may need to use subqueries or joins to solve this problem.

SELECT Users.user_id, Users.username
FROM Users
JOIN Orders ON Users.user_id = Orders.order_id
JOIN Order_Items ON Orders.order_id = Order_Items.order_id
JOIN Products ON Order_Items.product_id = Products.product_id
JOIN Categories ON Products.category_id = Categories.category_id
GROUP BY Users.user_id
HAVING COUNT(DISTINCT Categories.category_id) = (SELECT COUNT(category_id) FROM Categories);

-- Problem 7: Retrieve the products that have not received any reviews
-- Write an SQL query to retrieve the products that have not received any reviews.
-- The result should include the product ID and product name.
-- Hint: You may need to use subqueries or left joins to solve this problem.
SELECT Products.product_id, Products.product_name
FROM Products
LEFT JOIN Reviews ON Products.product_id = Reviews.product_id
WHERE Reviews.review_id IS NULL;

-- Problem 8: Retrieve the users who have made consecutive orders on consecutive days
-- Write an SQL query to retrieve the users who have made consecutive orders on consecutive days.
-- The result should include the user ID and username.
-- Hint: You may need to use subqueries or window functions to solve this problem.
-- Hint: You may need to use subqueries or window functions to solve this problem.

22 changes: 22 additions & 0 deletions sql/task3.sql
Original file line number Diff line number Diff line change
Expand Up @@ -3,15 +3,37 @@
-- The result should include the category ID, category name, and the total sales amount.
-- Hint: You may need to use subqueries, joins, and aggregate functions to solve this problem.

SELECT Categories.category_id, Categories.category_name, SUM(Orders.total_amount) AS total_sales
FROM Categories
JOIN Products ON Categories.category_id = Products.category_id
JOIN Order_Items ON Products.product_id = Order_Items.product_id
JOIN Orders ON Order_Items.order_id = Orders.order_id
GROUP BY Categories.category_id, Categories.category_name
ORDER BY total_sales DESC
LIMIT 3

-- Problem 10: Retrieve the users who have placed orders for all products in the Toys & Games
-- Write an SQL query to retrieve the users who have placed orders for all products in the Toys & Games
-- The result should include the user ID and username.
-- Hint: You may need to use subqueries, joins, and aggregate functions to solve this problem.

SELECT Users.user_id, Users.username
FROM Users
JOIN Orders ON Users.user_id = Orders.user_id
JOIN Order_Items ON Orders.order_id = Order_Items.order_id
JOIN Products ON Order_Items.product_id = Products.product_id
JOIN Categories ON Products.category_id = Categories.category_id
GROUP BY Users.user_id, Users.username
HAVING COUNT(DISTINCT Products.product_id) = (SELECT COUNT(DISTINCT product_id) FROM Products WHERE category_id = 5);

-- Problem 11: Retrieve the products that have the highest price within each category
-- Write an SQL query to retrieve the products that have the highest price within each category.
-- The result should include the product ID, product name, category ID, and price.
-- Hint: You may need to use subqueries, joins, and window functions to solve this problem.
SELECT product_id, product_name, category_id, price
FROM (SELECT *, ROW_NUMBER() OVER (PARTITION BY category_id ORDER BY price DESC) AS price_rows
FROM Products) AS Ranked_Prices
WHERE price_rows = 1;

-- Problem 12: Retrieve the users who have placed orders on consecutive days for at least 3 days
-- Write an SQL query to retrieve the users who have placed orders on consecutive days for at least 3 days.
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