Assignment 1 updated

02_activities/assignments/Cohort_8/assignment1.sql

@@ -4,17 +4,24 @@
 
 --SELECT
 /* 1. Write a query that returns everything in the customer table. */
-
+SELECT * FROM  customer;
 
 
 /* 2. Write a query that displays all of the columns and 10 rows from the cus- tomer table, 
 sorted by customer_last_name, then customer_first_ name. */
 
+SELECT * FROM customer
+ORDER BY customer_last_name, customer_first_name DESC -- z->a
+LIMIT 10; -- only 10 rows
 
 
 --WHERE
 /* 1. Write a query that returns all customer purchases of product IDs 4 and 9. */
 
+SELECT * 
+FROM customer_purchases
+WHERE product_id IN (4,9); 
+
 
 
 /*2. Write a query that returns all customer purchases and a new calculated column 'price' (quantity * cost_to_customer_per_qty), 
@@ -23,6 +30,12 @@ filtered by customer IDs between 8 and 10 (inclusive) using either:
 	2.  one condition using BETWEEN
 */
 -- option 1
+SELECT * , (quantity * cost_to_customer_per_qty)AS price
+FROM customer_purchases WHERE customer_id >= 8 AND customer_id <= 10;
+
+
+--AND customer_id -- returns nothing
+
 
 
 -- option 2
@@ -34,19 +47,41 @@ filtered by customer IDs between 8 and 10 (inclusive) using either:
 Using the product table, write a query that outputs the product_id and product_name
 columns and add a column called prod_qty_type_condensed that displays the word “unit” 
 if the product_qty_type is “unit,” and otherwise displays the word “bulk.” */
-
-
+SELECT product_id, product_name,
+CASE WHEN product_qty_type = 'unit' THEN 'unit'
+	ELSE 'bulk'
+	END as prod_qty_type_condensed
+	FROM product ;
 
 /* 2. We want to flag all of the different types of pepper products that are sold at the market. 
 add a column to the previous query called pepper_flag that outputs a 1 if the product_name 
 contains the word “pepper” (regardless of capitalization), and otherwise outputs 0. */
 
-
+SELECT product_id, product_name,
+CASE WHEN product_qty_type = 'unit' THEN 'unit'
+	ELSE 'bulk'
+	END as prod_qty_type_condensed,
+CASE WHEN LOWER(product_name) LIKE '%pepper%' THEN 1
+ELSE 0 
+END AS pepper_flag 
+FROM product ;
 
 --JOIN
 /* 1. Write a query that INNER JOINs the vendor table to the vendor_booth_assignments table on the 
 vendor_id field they both have in common, and sorts the result by vendor_name, then market_date. */
 
+SELECT 
+v.vendor_name, 
+v.vendor_id, 
+vba.market_date,
+vba.booth_number
+
+FROM  vendor v
+
+INNER JOIN vendor_booth_assignments vba
+	ON v.vendor_id = vba.vendor_id 
+
+	ORDER BY v.vendor_name, vba.market_date ;
 
 
 
@@ -56,15 +91,29 @@ vendor_id field they both have in common, and sorts the result by vendor_name, t
 /* 1. Write a query that determines how many times each vendor has rented a booth 
 at the farmer’s market by counting the vendor booth assignments per vendor_id. */
 
-
+SELECT vendor_id
+,COUNT(*) as booth_rentals 
+FROM vendor_booth_assignments
+GROUP BY vendor_id;
 
 /* 2. The Farmer’s Market Customer Appreciation Committee wants to give a bumper 
 sticker to everyone who has ever spent more than $2000 at the market. Write a query that generates a list 
 of customers for them to give stickers to, sorted by last name, then first name. 
 
 HINT: This query requires you to join two tables, use an aggregate function, and use the HAVING keyword. */
 
+SELECT c.customer_first_name, c.customer_last_name, c.customer_id 
+,SUM(cp.quantity*cp.cost_to_customer_per_qty) as total_cost
+
+FROM customer c 
+
+INNER JOIN customer_purchases cp
+	ON cp.customer_id = c.customer_id
 
+GROUP BY c.customer_id, c.customer_first_name, c.customer_last_name
+HAVING SUM(cp.quantity*cp.cost_to_customer_per_qty)>2000
+
+ORDER BY c.customer_last_name, c.customer_first_name ;
 
 --Temp Table
 /* 1. Insert the original vendor table into a temp.new_vendor and then add a 10th vendor: 
@@ -78,6 +127,15 @@ When inserting the new vendor, you need to appropriately align the columns to be
 VALUES(col1,col2,col3,col4,col5) 
 */
 
+DROP TABLE IF EXISTS temp.new_vendor ;
+
+CREATE TABLE temp.new_vendor AS 
+
+SELECT * FROM vendor ;
+INSERT INTO new_vendor (vendor_id, vendor_name, vendor_type, vendor_owner_first_name, vendor_owner_last_name)
+VALUES (10, 'Thomass Superfood Store', 'Fresh Focused', 'Thomas', 'Rosenthal') ;
+SELECT * FROM new_vendor ;
+
 
 
 -- Date