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2 changes: 1 addition & 1 deletion Lectures/lecture25.tex
Original file line number Diff line number Diff line change
Expand Up @@ -379,7 +379,7 @@ \subsection{Метод Якоби}
Пусть $B_k'$ будет матрица $\beta$ в штрихованном базисе.
Тогда $B_{k+1} = C^t B_{k+1}' C$, а значит
\[
\Delta_{k+1} = \det B_{k+1} = \det B_{k+1}' \det C^2 = \det B_{k+1} = \beta(e_1',e_1')\ldots \beta(e_{k+1}',e_{k+1}')
\Delta_{k+1} = \det B_{k+1} = \det B_{k+1}' \det C^2 = \det B_{k+1}' = \beta(e_1',e_1')\ldots \beta(e_{k+1}',e_{k+1}')
\]
Что доказывает оставшееся равенство.
\end{proof}
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