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초급반 / 김민지 / 단어뒤집기2-17413, 파일정리-20291, ZOAC-30436 #108
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arenran02
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| Original file line number | Diff line number | Diff line change |
|---|---|---|
| @@ -0,0 +1,26 @@ | ||
| #include <iostream> | ||
| #include <map> | ||
| #include <string> | ||
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| int main() { | ||
| int N; | ||
| std::cin >> N; | ||
| std::map<std::string, int> extensionCount; | ||
|
|
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| for (int i = 0; i < N; ++i) { | ||
| std::string filename; | ||
| std::cin >> filename; | ||
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| size_t pos = filename.rfind('.'); | ||
| if (pos != std::string::npos) { | ||
| std::string extension = filename.substr(pos + 1); | ||
| ++extensionCount[extension]; | ||
| } | ||
| } | ||
|
|
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| for (const auto& pair : extensionCount) { | ||
| std::cout << pair.first << " " << pair.second << "\n"; | ||
| } | ||
|
|
||
| return 0; | ||
| } |
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std::map<std::string, int>을 사용하여 고유한 파일 확장자를 키로, 해당 확장자를 가진 파일의 개수를 값으로 저장하는 방식으로 문제를 해결한 것이 좋다고 생각합니다.