52-tgyuuAn

tgyuuAn/BFS/과외맨.py

@@ -0,0 +1,126 @@
+import sys
+from collections import deque
+
+def input(): return sys.stdin.readline().rstrip()
+
+N = int(input())
+
+board = []
+idx = 1
+for row in range(N):
+    row_tiles = []
+    # 홀수 줄 일 경우 N개가 그대로 들어옴
+    if row%2==0:
+        for col in range(N):
+            temp = list(input().split())
+            temp.append(idx)
+            tile = tuple(temp)
+
+            row_tiles.append(tile)
+            idx += 1
+
+    # 짝수 줄 일 경우 N-1개가 들어옴
+    else:
+        for col in range(N-1):
+            temp = list(input().split())
+            temp.append(idx)
+            tile = tuple(temp)
+
+            row_tiles.append(tile)
+            idx += 1
+
+    board.append(row_tiles)
+
+parent_tile = [-1 for _ in range(idx)]
+
+odd_dx = [-1, -1, 0, 0, 1, -1]
+odd_dy = [0, 1, -1, 1, 0, 1]
+
+even_dx = [0, 1, -1, 1, 0, 1]
+even_dy = [-1, -1, 0, 0, 1, 1]
+
+now = (1, (0, 0), 1) # 타일 번호, 현재 타일 좌표, 현재 이동한 횟수
+visited = set()
+deq = deque([now])
+biggest_number_tile = -1
+biggest_number_count = int(1e9)
+while deq:
+    now_tile, tile_pos, now_count = deq.popleft()
+    now_x = tile_pos[0]
+    now_y = tile_pos[1]
+
+    if now_tile > biggest_number_tile:
+        biggest_number_tile = now_tile
+        biggest_number_count = now_count
+
+    if now_tile == idx-1:
+        print(now_count)
+        ans_que = deque([])
+        now = now_tile
+        while now != 1:
+            ans_que.appendleft(now)
+            now = parent_tile[now]
+        ans_que.appendleft(1)
+        print(*ans_que)
+        break
+
+    # 홀수번 째 줄 일 경우,
+    if now_y%2 == 0:
+
+        for dir in range(6):
+            new_x = now_x + odd_dx[dir]
+            new_y = now_y + odd_dy[dir]
+
+            if new_x < 0 or new_x >= N: continue
+            if new_y%2 == 1 and new_x >= N-1: continue
+            if new_y < 0 or new_y >= N: continue
+
+            new_tile = board[new_y][new_x]
+            new_tile_idx = new_tile[-1]
+
+            if new_tile_idx in visited: continue
+            if dir in (0,1,5) and board[now_y][now_x][0] != board[new_y][new_x][1]: continue
+            if dir in (2,3,4) and board[now_y][now_x][1] != board[new_y][new_x][0]: continue
+
+            visited.add(new_tile_idx)
+            parent_tile[new_tile_idx] = now_tile
+            deq.append((new_tile_idx, (new_x, new_y), now_count+1))
+
+    # 짝수번 째 줄 일 경우,
+    else:
+        for dir in range(6):
+            new_x = now_x + even_dx[dir]
+            new_y = now_y + even_dy[dir]
+
+            if new_x < 0 or new_x >= N: continue
+            if new_y%2 == 1 and new_x >= N-1: continue
+            if new_y < 0 or new_y >= N: continue
+
+            new_tile = board[new_y][new_x]
+            new_tile_idx = new_tile[-1]
+
+            if new_tile_idx in visited: continue
+            if dir in (0,2,4) and board[now_y][now_x][0] != board[new_y][new_x][1]: continue
+            if dir in (1,3,5) and board[now_y][now_x][1] != board[new_y][new_x][0]: continue
+
+            visited.add(new_tile_idx)
+            parent_tile[new_tile_idx] = now_tile
+            deq.append((new_tile_idx, (new_x, new_y), now_count+1))
+
+else:
+    print(biggest_number_count)
+    ans_que = deque([])
+    now = biggest_number_tile
+    while now != 1:
+        ans_que.appendleft(now)
+        now = parent_tile[now]
+    ans_que.appendleft(1)
+    print(*ans_que)
+
+# 홀수번 째 줄에서 이동할 때,
+# 짝수번 째 줄로 행 이동을 할 때에는 N번째 인덱스 뿐 아니라 N-1번째 인덱스로도 접근 가능.
+# 당연하겠지만 열의 0번 인덱스에서는 0번으로만 이동할 수 있음.
+# 마찬가지로 열의 마지막 인덱스에서는 N-1로만 이동할 수 있음.
+
+# 짝수번 째 줄에서 홀수번 째 줄으로 행 이동할 때에는,
+# N번째 줄 뿐아니라, N+1번째 줄로도 이동 가능.

tgyuuAn/README.md

@@ -48,4 +48,5 @@
 | 44차시 | 2023.03.13 |  트라이  | <a href="https://www.acmicpc.net/problem/14725">개미굴</a> | https://github.com/AlgoLeadMe/AlgoLeadMe-1/pull/159
 | 45차시 | 2023.03.16 |  트라이  | <a href="https://www.acmicpc.net/problem/31413">트라이</a> | https://github.com/AlgoLeadMe/AlgoLeadMe-1/pull/162
 | 51차시 | 2023.04.07 |  BFS  | <a href="https://www.acmicpc.net/problem/5213">과외맨</a> | https://github.com/AlgoLeadMe/AlgoLeadMe-1/pull/179
+| 52차시 | 2023.05.06 |  위상정렬  | <a href="https://www.acmicpc.net/problem/1516">게임 개발</a> | https://github.com/AlgoLeadMe/AlgoLeadMe-1/pull/182
 ---

tgyuuAn/위상정렬/게임 개발.py

@@ -0,0 +1,44 @@
+import sys
+
+def input(): return sys.stdin.readline()
+INF = int(1e9)
+
+visited = set()
+N = int(input())
+indegree = [[0,set()] for _ in range(N+1)]
+receipe = [[] for _ in range(N+1)]
+outdegree = [[] for _ in range(N+1)]
+answer = [INF for _ in range(N+1)]
+can_build = []
+
+for idx in range(1,N+1):
+    _input = list(map(int,input().split()))
+    indegree[idx][0] = _input[0]
+    receipe[idx] = _input[1:-1]
+    indegree[idx][1] = set(_input[1:-1])
+    for out in _input[1:-1]:
+        outdegree[out].append(idx)
+
+    if len(indegree[idx][1]) == 0:
+        can_build.append(idx)
+        visited.add(idx)
+        answer[idx] = _input[0]
+
+while can_build:
+    now = can_build.pop()
+
+    for next_building in outdegree[now]:
+        indegree[next_building][1].discard(now)
+
+        if len(indegree[next_building][1]) == 0 and next_building not in visited:
+            can_build.append(next_building)
+
+            max_temp = -1
+            for ingredient in receipe[next_building]:
+                max_temp = max(max_temp, answer[ingredient])
+
+            answer[next_building] = min(answer[next_building], max_temp + indegree[next_building][0])
+            visited.add(next_building)
+
+for ans in answer[1:]:
+    print(ans)