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The expression inside a decltype() will always be a cpp_unexposed_expression and the type of the expression is not exposed either. On a related note, cpp_decltype_auto_type will never be created, decltype(auto) will create a simple cpp_auto_type instead.
The text was updated successfully, but these errors were encountered:
libclang_parser
The expression inside a
decltype()
will always be acpp_unexposed_expression
and the type of the expression is not exposed either. On a related note,cpp_decltype_auto_type
will never be created,decltype(auto)
will create a simplecpp_auto_type
instead.The text was updated successfully, but these errors were encountered: