Apply suggestions from code review

Co-authored-by: Therese Magnusson <[email protected]>

Author: mnd999

modules/ROOT/pages/errors/gql-errors/22NC4.adoc

@@ -9,7 +9,7 @@ A label cannot be both "identifying" (used to uniquely identify nodes) and "impl
 Attempting to define a label as both will result in this error, as it creates ambiguity in the schema definition and node identification process.
 
 == Example scenario
-For example, try to set a graph type which defines the node element types 'Person and 'Student' with the label 'Person' also declared as an implied label on the 'Student' node element type:
+For example, try to set a graph type which defines the node element types 'Person' and 'Student' with the label 'Person' also declared as an implied label on the 'Student' node element type:
 
 [source,cypher]
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modules/ROOT/pages/errors/gql-errors/22NC6.adoc

@@ -1,14 +1,14 @@
 = 22NC6
 
 == Status description
-The independent constraint `{ <<constrDescrOrName>> }`` was defined using the same label `{ <<label>> }` as a node type element.
+The independent constraint `{ <<constrDescrOrName>> }` was defined using the same label `{ <<label>> }` as a node type element.
 
 == Explanation
 This error occurs when a label is used both as an identifying label (defining a node type element) and as part of an independent constraint.
 A label cannot serve as both an identifying label and be referenced in an independent constraint at the same time.
 
 == Example scenario
-For example, try to set an existance constraint on a property for the label `:Person`` where `:Person` is also defined as an identifying label in the graph type:
+For example, try to set an existance constraint on a property for the label `:Person` where `:Person` is also defined as an identifying label in the graph type:
 
 [source,cypher]
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modules/ROOT/pages/errors/gql-errors/22NC7.adoc

@@ -8,7 +8,7 @@ This error occurs when a relationship type is used both as an identifying relaio
 A label cannot serve as both an identifying label and be referenced in an independent constraint at the same time.
 
 == Example scenario
-For example, try to set an existance constraint on a property for the relationship type `:REL`` where `:REL` is also defined as an identifying relationship type in the graph type:
+For example, try to set an existance constraint on a property for the relationship type `:REL` where `:REL` is also defined as an identifying relationship type in the graph type:
 
 [source,cypher]
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