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Problem3.java
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/***
* This problem was asked by Google.
*
* Given the root to a binary tree, implement serialize(root), which serializes the tree into a string, and deserialize(s), which deserializes the string back into the tree.
*
* For example, given the following Node class
*
* class Node:
* def __init__(self, val, left=None, right=None):
* self.val = val
* self.left = left
* self.right = right
* The following test should pass:
*
* node = Node('root', Node('left', Node('left.left')), Node('right'))
* assert deserialize(serialize(node)).left.left.val == 'left.left'
*/
import java.util.Arrays;
import java.util.LinkedList;
import java.util.Queue;
public class Problem3 {
private static final String DELIMITER = ",";
private static final String NULL_VALUE = "null";
public static void main(String[] args) {
Node root =
new Node(10,
new Node(5,
new Node(3,
new Node(2,
new Node(1),
null),
new Node(4)
),
new Node(7,
new Node(6),
new Node(9,
new Node(8),
null)
)
),
new Node(15,
new Node(12,
new Node(11),
new Node(13,
null,
new Node(14)
)
),
new Node(17,
new Node(16),
new Node(18,
null,
new Node(19)
)
)
)
);
// Testing solution
String serialized = serialize(root);
Node deserialized = deserialize(serialized);
String serializedAgain = serialize(deserialized);
if (serialized.equals(serializedAgain))
System.out.println("Successful");
else
System.out.println("Failed");
Node deserializedEfficiently = deserialized(serialized);
String serializedEfficiently = serialize(deserializedEfficiently);
if (serialized.equals(serializedEfficiently))
System.out.println("Successful");
else
System.out.println("Failed");
}
public static String serialize(Node root) {
StringBuffer sb = new StringBuffer();
serialize(root, sb);
return sb.toString();
}
public static Node deserialize(String serialized) {
String[] arr = serialized.split(DELIMITER);
Queue<String> values = new LinkedList<>(Arrays.asList(arr));
return deserialize(values);
}
// Helper Methods
private static void serialize(Node root, StringBuffer sb) {
if (root == null) sb.append(NULL_VALUE + DELIMITER);
else {
sb.append(root.value + DELIMITER);
serialize(root.left, sb);
serialize(root.right, sb);
}
}
private static Node deserialize(Queue<String> values) {
if (values.isEmpty()) return null;
String v1 = values.poll();
if (v1.equals(NULL_VALUE)) return null;
int value = Integer.parseInt(v1);
Node root = new Node(value);
root.left = deserialize(values);
root.right = deserialize(values);
return root;
}
// Efficient Deserialization
public static Node deserialized (String serialized) {
String[] values = serialized.split(DELIMITER);
int[] index = {0};
return deserialized(values, index);
}
private static Node deserialized (String[] values, int[] i) {
if (i[0] == values.length - 1 || values[i[0]].equals(NULL_VALUE))
return null;
int value = Integer.parseInt(values[i[0]]);
Node root = new Node(value);
i[0]++;
root.left = deserialized(values, i);
i[0]++;
root.right = deserialized(values, i);
return root;
}
}
class Node {
public Node left, right;
public int value;
public Node(int value) {
this(value, null, null);
}
public Node(int value, Node left, Node right) {
this.value = value;
this.left = left;
this.right = right;
}
}