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q160-intersection-of-two-linked-lists.swift
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//
// q160-intersection-of-two-linked-lists.swift
// leetcode-swift
// Source* : https://leetcode.com/problems/intersection-of-two-linked-lists/
// Category* : LinkedList
//
// Created by Tianyu Wang on 16/7/5.
// Github : http://github.com/wty21cn
// Website : http://wty.im
// Linkedin : https://www.linkedin.com/in/wty21cn
// Mail : mailto:[email protected]
/**********************************************************************************
*
* Write a program to find the node at which the intersection of two singly linked lists begins.
*
* For example, the following two linked lists:
*
*
* A: a1 → a2
* ↘
* c1 → c2 → c3
* ↗
* B: b1 → b2 → b3
*
* begin to intersect at node c1.
*
* Notes:
*
* If the two linked lists have no intersection at all, return null.
* The linked lists must retain their original structure after the function returns.
* You may assume there are no cycles anywhere in the entire linked structure.
* Your code should preferably run in O(n) time and use only O(1) memory.
*
**********************************************************************************/
import Foundation
struct q160 {
class Solution {
func proceedHead(_ head: ListNode?, step: Int) -> ListNode? {
var head = head, step = step
while step > 0 {
head = head?.next
step -= 1
}
return head
}
func getIntersectionNode(_ headA: ListNode?, _ headB: ListNode?) -> ListNode? {
if headA == nil || headB == nil { return nil }
var headA = headA, headB = headB
let lengthA = headA!.length
let lengthB = headB!.length
headA = proceedHead(headA, step: max(lengthA, lengthB) - lengthB)
headB = proceedHead(headB, step: max(lengthA, lengthB) - lengthA)
while headA != nil && headB != nil {
if headA === headB {
return headA
} else {
headA = headA!.next
headB = headB!.next
}
}
return nil
}
}
static func getSolution() -> Void {
var headA = LinkedListHelper.buildLinkedList(withNodes: [1,2,3,7,8,9])
var headB = LinkedListHelper.buildLinkedList(withNodes: [4,5,6])
headB?.next?.next?.next = headA?.next?.next?.next
print(headA ?? "")
print(headB ?? "")
print(Solution().getIntersectionNode(headA, headB) ?? "")
headA = LinkedListHelper.buildLinkedList(withNodes: [1,2,3,7,8,9])
headB = headA?.next?.next
print(headA ?? "")
print(headB ?? "")
print(Solution().getIntersectionNode(headA, headB) ?? "")
headA = LinkedListHelper.buildLinkedList(withNodes: [1,2,3,7,8,9])
headB = LinkedListHelper.buildLinkedList(withNodes: [4,5,6])
print(headA ?? "")
print(headB ?? "")
print(Solution().getIntersectionNode(headA, headB) ?? "")
print(Solution().getIntersectionNode(nil, nil) ?? "")
}
}