I'm not sure if there's already a way to do this and I'm just missing it... in the image below, the number 19 shouldn't be there, right? There's no word that starts there, either down or across.
I'd be glad to take a look and work on this (this is an incredible tool!), I just don't want to duplicate work if there's already a way.
I believe the relevant code is here:
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function updateLabelsAndClues() { |
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let count = 1; |
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for (let i = 0; i < xw.rows; i++) { |
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for (let j = 0; j < xw.cols; j++) { |
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let isAcross = false; |
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let isDown = false; |
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if (xw.fill[i][j] != BLACK) { |
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isDown = i == 0 || xw.fill[i - 1][j] == BLACK; |
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isAcross = j == 0 || xw.fill[i][j - 1] == BLACK; |
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} |
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const grid = document.getElementById("grid"); |
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let currentCell = grid.querySelector('[data-row="' + i + '"]').querySelector('[data-col="' + j + '"]'); |
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if (isAcross || isDown) { |
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currentCell.firstChild.innerHTML = count; // Set square's label to the count |
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count++; |
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} else { |
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currentCell.firstChild.innerHTML = ""; |
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} |
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if (isAcross) { |
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xw.clues[[i, j, ACROSS]] = xw.clues[[i, j, ACROSS]] || DEFAULT_CLUE; |
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} else { |
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delete xw.clues[[i, j, ACROSS]]; |
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} |
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if (isDown) { |
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xw.clues[[i, j, DOWN]] = xw.clues[[i, j, DOWN]] || DEFAULT_CLUE; |
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} else { |
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delete xw.clues[[i, j, DOWN]]; |
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} |
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} |
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} |
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} |
