From 5b2601486fdb8c81ca16bab8722596953521cb3a Mon Sep 17 00:00:00 2001
From: Patrizia Trammell <patrizia.trammell@yahoo.com>
Date: Wed, 2 Apr 2025 20:41:42 +0200
Subject: [PATCH] lab done

---
 index.js | 61 ++++++++++++++++++++++++++++++++++++++++++++++++++++++++
 1 file changed, 61 insertions(+)

diff --git a/index.js b/index.js
index 6b0fec3ad..4f7feb640 100644
--- a/index.js
+++ b/index.js
@@ -1,7 +1,68 @@
 // Iteration 1: Names and Input
+//1.1 Create a variable hacker1 with the driver's name.
+//1.2 Print "The driver's name is XXXX".
+//1.3 Create a variable hacker2 with the navigator's name.
+//1.4 Print "The navigator's name is YYYY". 
+
+//1st attempt - took it too literal, I need to place names and use the drivers name as the string
+//const hacker1 = "The driver's name";
+//const hacker2 = "The navigator's name";
+
+const hacker1 = 'John';
+const hacker2 = 'Claus';
+
+console.log("The driver's Name is " + hacker1);
+console.log("The navigator's Name is " + hacker2);
 
 
 // Iteration 2: Conditionals
+//2.1. Depending on which name is longer, print:
+//The driver has the longest name, it has XX characters. or
+//It seems that the navigator has the longest name, it has XX characters. or
+//Wow, you both have equally long names, XX characters!.
+//***************
+//on my own I managed to figure this out, however the characters I did not. the xx i left in there for me
+//to think about the logic that is missing
 
 
+if (hacker1.length > hacker2.length) {
+    console.log("The driver has the longest name, it has " + hacker1.length + " characters.");
+} else if (hacker2.length > hacker1.length) {
+    console.log("It seems that the navigator has the longest name, it has " + hacker2.length + " characters.")
+} else {
+    console.log("Wow, you both have equally long names, " + hacker1.length + " characters!");
+}
+
 // Iteration 3: Loops
+//3.1 Print the characters of the driver's name, separated by space, and in capital letters, i.e., "J O H N".
+//3.2 Print all the characters of the navigator's name in reverse order, i.e., "nhoJ".
+//3.3 Depending on the lexicographic order of the strings, print:
+//The driver's name goes first.
+//Yo, the navigator goes first, definitely.
+//What?! You both have the same name?
+
+let charChange = "";
+let backWards = "";
+
+for (let i = 0; i < hacker1.length; i++) {
+const sepSpace = hacker1[i].toUpperCase();
+console.log(sepSpace);
+charChange += sepSpace + " ";
+}
+
+for (let i = hacker1.length -1; i > -1; i--) {
+const sepSpace = hacker1[i].toUpperCase();
+backWards += sepSpace + " ";
+}
+
+console.log(charChange);
+console.log(backWards);
+
+if (hacker1 > hacker2) {
+    console.log("The driver's name goes first.");
+} else if (hacker1 < hacker2) {
+    console.log("Yo, the navigator goes first, definitely.");
+} else {
+   console.log("What?! You both have the same name?");
+}
+