diff --git a/your-code/.ipynb_checkpoints/challenges-checkpoint.ipynb b/your-code/.ipynb_checkpoints/challenges-checkpoint.ipynb new file mode 100644 index 0000000..31c854e --- /dev/null +++ b/your-code/.ipynb_checkpoints/challenges-checkpoint.ipynb @@ -0,0 +1,726 @@ +{ + "cells": [ + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## Challenge 1: Tuples\n", + "\n", + "#### Do you know you can create tuples with only one element?\n", + "\n", + "**In the cell below, define a variable `tup` with a single element `\"I\"`.**\n" + ] + }, + { + "cell_type": "code", + "execution_count": 1, + "metadata": { + "tags": [] + }, + "outputs": [], + "source": [ + "tup = (\"I\",)" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "#### Print the type of `tup`. \n", + "\n", + "Make sure its type is correct (i.e. *tuple* instead of *str*)." + ] + }, + { + "cell_type": "code", + "execution_count": 9, + "metadata": { + "tags": [] + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "\n" + ] + } + ], + "source": [ + "print(type(tup))" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "#### Now try to append the following elements to `tup`. \n", + "\n", + "Are you able to do it? Explain.\n", + "\n", + "```\n", + "\"r\", \"o\", \"n\", \"h\", \"a\", \"c\", \"k',\n", + "```" + ] + }, + { + "cell_type": "code", + "execution_count": 11, + "metadata": { + "scrolled": true, + "tags": [] + }, + "outputs": [ + { + "ename": "AttributeError", + "evalue": "'tuple' object has no attribute 'append'", + "output_type": "error", + "traceback": [ + "\u001b[1;31m---------------------------------------------------------------------------\u001b[0m", + "\u001b[1;31mAttributeError\u001b[0m Traceback (most recent call last)", + "Cell \u001b[1;32mIn[11], line 2\u001b[0m\n\u001b[0;32m 1\u001b[0m tup \u001b[38;5;241m=\u001b[39m (\u001b[38;5;124m\"\u001b[39m\u001b[38;5;124mI\u001b[39m\u001b[38;5;124m\"\u001b[39m,)\n\u001b[1;32m----> 2\u001b[0m \u001b[43mtup\u001b[49m\u001b[38;5;241;43m.\u001b[39;49m\u001b[43mappend\u001b[49m(\u001b[38;5;124m\"\u001b[39m\u001b[38;5;124mr\u001b[39m\u001b[38;5;124m\"\u001b[39m)\n\u001b[0;32m 4\u001b[0m \u001b[38;5;66;03m# It failed becaused Tuples are immutable and you cannot change their contents.\u001b[39;00m\n\u001b[0;32m 5\u001b[0m \u001b[38;5;66;03m# But to append elements, we can use List which is mutable\u001b[39;00m\n", + "\u001b[1;31mAttributeError\u001b[0m: 'tuple' object has no attribute 'append'" + ] + } + ], + "source": [ + "tup = (\"I\",)\n", + "tup.append(\"r\")\n", + "\n", + "# It failed becaused Tuples are immutable and you cannot change their contents.\n", + "# But to append elements, we can use List which is mutable" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "#### How about re-assign a new value to an existing tuple?\n", + "\n", + "Re-assign the following elements to `tup`. Are you able to do it? Explain.\n", + "\n", + "```\n", + "\"I\", \"r\", \"o\", \"n\", \"h\", \"a\", \"c\", \"k\"\n", + "```" + ] + }, + { + "cell_type": "code", + "execution_count": 13, + "metadata": { + "tags": [] + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "('I', 'r', 'o', 'n', 'h', 'a', 'c', 'k')\n" + ] + } + ], + "source": [ + "tup = (\"I\", \"r\", \"o\", \"n\", \"h\", \"a\", \"c\", \"k\")\n", + "print(tup)" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "You can re-assign a new value to a tuple variable, because this is not modifying the existing tuple, but rather you are simply making the variable tup point to a new tuple." + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "#### Split `tup` into `tup1` and `tup2` with 4 elements in each. \n", + "\n", + "`tup1` should be `(\"I\", \"r\", \"o\", \"n\")` and `tup2` should be `(\"h\", \"a\", \"c\", \"k\")`.\n", + "\n", + "*Hint: use positive index numbers for `tup1` assignment and use negative index numbers for `tup2` assignment. Positive index numbers count from the beginning whereas negative index numbers count from the end of the sequence.*\n", + "\n", + "Also print `tup1` and `tup2`." + ] + }, + { + "cell_type": "code", + "execution_count": 16, + "metadata": { + "tags": [] + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "tup1 = ('I', 'r', 'o', 'n')\n", + "tup2 = ('h', 'a', 'c', 'k')\n" + ] + } + ], + "source": [ + "# Slice using positive indices for tup1 (first 4 elements)\n", + "tup1 = tup[0:4]\n", + "\n", + "# Slice using negative indices for tup2 (last 4 elements)\n", + "tup2 = tup[-4:] \n", + "\n", + "print(\"tup1 =\", tup1)\n", + "print(\"tup2 =\", tup2)" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "#### Add `tup1` and `tup2` into `tup3` using the `+` operator.\n", + "\n", + "Then print `tup3` and check if `tup3` equals to `tup`." + ] + }, + { + "cell_type": "code", + "execution_count": 18, + "metadata": { + "tags": [] + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "tup: ('I', 'r', 'o', 'n', 'h', 'a', 'c', 'k')\n", + "tup3: ('I', 'r', 'o', 'n', 'h', 'a', 'c', 'k')\n" + ] + } + ], + "source": [ + "tup3 = tup1 + tup2\n", + "print(\"tup: \",tup)\n", + "print(\"tup3: \",tup3)" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "tup3 is equal to the tup" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "#### Count the number of elements in `tup1` and `tup2`. Then add the two counts together and check if the sum is the same as the number of elements in `tup3`." + ] + }, + { + "cell_type": "code", + "execution_count": 23, + "metadata": { + "tags": [] + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "The number of elements in tup1 and tup2 is 8\n", + "The number of elements in tup3 is 8\n" + ] + } + ], + "source": [ + "count_tup1_tup2 = len(tup1) + len(tup2)\n", + "count_tup3 = len(tup3)\n", + "\n", + "print(\"The number of elements in tup1 and tup2 is\", count_tup1_tup2)\n", + "print(\"The number of elements in tup3 is\", count_tup3)" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "#### What is the index number of `\"h\"` in `tup3`?" + ] + }, + { + "cell_type": "code", + "execution_count": null, + "metadata": {}, + "outputs": [], + "source": [ + "# Your code here" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "#### Now, use a FOR loop to check whether each letter in the following list is present in `tup3`:\n", + "\n", + "```\n", + "letters = [\"a\", \"b\", \"c\", \"d\", \"e\"]\n", + "```\n", + "\n", + "For each letter you check, print `True` if it is present in `tup3` otherwise print `False`.\n", + "\n", + "*Hint: you only need to loop `letters`. You don't need to loop `tup3` because there is a Python operator `in` you can use. See [reference](https://stackoverflow.com/questions/17920147/how-to-check-if-a-tuple-contains-an-element-in-python).*" + ] + }, + { + "cell_type": "code", + "execution_count": null, + "metadata": {}, + "outputs": [], + "source": [ + "# Your code here" + ] + }, + { + "cell_type": "code", + "execution_count": null, + "metadata": {}, + "outputs": [], + "source": [ + "# Your code here" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "#### How many times does each letter in `letters` appear in `tup3`?\n", + "\n", + "Print out the number of occurrence of each letter." + ] + }, + { + "cell_type": "code", + "execution_count": null, + "metadata": {}, + "outputs": [], + "source": [ + "# Your code here" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## Challenge 2: Sets\n", + "\n", + "There are a lot to learn about Python Sets and the information presented in the lesson is limited due to its length. To learn Python Sets in depth you are strongly encouraged to review the W3Schools tutorial on [Python Sets Examples and Methods](https://www.w3schools.com/python/python_sets.asp) before you work on this lab. Some difficult questions in this lab have their solutions in the W3Schools tutorial.\n", + "\n", + "#### First, import the Python `random` library." + ] + }, + { + "cell_type": "code", + "execution_count": null, + "metadata": {}, + "outputs": [], + "source": [ + "import random" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "#### In the cell below, create a list named `sample_list_1` with 80 random values. \n", + "\n", + "Requirements:\n", + "\n", + "* Each value is an integer falling between 0 and 100.\n", + "* Each value in the list is unique.\n", + "\n", + "Print `sample_list_1` to review its values\n", + "\n", + "*Hint: use `random.sample` ([reference](https://docs.python.org/3/library/random.html#random.sample)).*" + ] + }, + { + "cell_type": "code", + "execution_count": null, + "metadata": {}, + "outputs": [], + "source": [ + "# Your code here" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "#### Convert `sample_list_1` to a set called `set1`. Print the length of the set. Is its length still 80?" + ] + }, + { + "cell_type": "code", + "execution_count": null, + "metadata": {}, + "outputs": [], + "source": [ + "# your code here" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "#### Create another list named `sample_list_2` with 80 random values.\n", + "\n", + "Requirements:\n", + "\n", + "* Each value is an integer falling between 0 and 100.\n", + "* The values in the list don't have to be unique.\n", + "\n", + "*Hint: Use a FOR loop.*" + ] + }, + { + "cell_type": "code", + "execution_count": null, + "metadata": {}, + "outputs": [], + "source": [ + "# your code here" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "#### Convert `sample_list_2` to a set called `set2`. Print the length of the set. Is its length still 80?" + ] + }, + { + "cell_type": "code", + "execution_count": null, + "metadata": {}, + "outputs": [], + "source": [ + "# Your code here" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "#### Identify the elements present in `set1` but not in `set2`. Assign the elements to a new set named `set3`." + ] + }, + { + "cell_type": "code", + "execution_count": null, + "metadata": {}, + "outputs": [], + "source": [ + "# Your code here" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "#### Identify the elements present in `set2` but not in `set1`. Assign the elements to a new set named `set4`." + ] + }, + { + "cell_type": "code", + "execution_count": null, + "metadata": {}, + "outputs": [], + "source": [ + "# Your code here" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "#### Now Identify the elements shared between `set1` and `set2`. Assign the elements to a new set named `set5`." + ] + }, + { + "cell_type": "code", + "execution_count": null, + "metadata": {}, + "outputs": [], + "source": [ + "# Your code here" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "#### What is the relationship among the following values:\n", + "\n", + "* len(set1)\n", + "* len(set2)\n", + "* len(set3)\n", + "* len(set4)\n", + "* len(set5)\n", + "\n", + "Use a math formular to represent that relationship. Test your formular with Python code." + ] + }, + { + "cell_type": "code", + "execution_count": null, + "metadata": {}, + "outputs": [], + "source": [ + "# Your code here" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "#### Create an empty set called `set6`." + ] + }, + { + "cell_type": "code", + "execution_count": null, + "metadata": {}, + "outputs": [], + "source": [ + "# Your code here" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "#### Add `set3` and `set5` to `set6` using the Python Set `update` method." + ] + }, + { + "cell_type": "code", + "execution_count": null, + "metadata": {}, + "outputs": [], + "source": [ + "# Your code here" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "#### Check if `set1` and `set6` are equal." + ] + }, + { + "cell_type": "code", + "execution_count": null, + "metadata": {}, + "outputs": [], + "source": [ + "# Your code here" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "#### Check if `set1` contains `set2` using the Python Set `issubset` method. Then check if `set1` contains `set3`.*" + ] + }, + { + "cell_type": "code", + "execution_count": null, + "metadata": {}, + "outputs": [], + "source": [ + "# Your code here" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "#### Using the Python Set `union` method, aggregate `set3`, `set4`, and `set5`. Then aggregate `set1` and `set2`. \n", + "\n", + "#### Check if the aggregated values are equal." + ] + }, + { + "cell_type": "code", + "execution_count": null, + "metadata": {}, + "outputs": [], + "source": [ + "# Your code here" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "#### Using the `pop` method, remove the first element from `set1`." + ] + }, + { + "cell_type": "code", + "execution_count": null, + "metadata": {}, + "outputs": [], + "source": [ + "# Your code here" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "#### Remove every element in the following list from `set1` if they are present in the set. Print the remaining elements.\n", + "\n", + "```\n", + "list_to_remove = [1, 9, 11, 19, 21, 29, 31, 39, 41, 49, 51, 59, 61, 69, 71, 79, 81, 89, 91, 99]\n", + "```" + ] + }, + { + "cell_type": "code", + "execution_count": null, + "metadata": {}, + "outputs": [], + "source": [ + "# Your code here" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "## BONUS - Challenge 3: Dictionaries\n", + "\n", + "In this challenge you will practice how to manipulate Python dictionaries. Before starting on this challenge, you are encouraged to review W3School's [Python Dictionary Examples and Methods](https://www.w3schools.com/python/python_dictionaries.asp).\n", + "\n", + "First thing you will practice is how to sort the keys in a dictionary. Unlike the list object, Python dictionary does not have a built-in *sort* method. You'll need to use FOR loops to to sort dictionaries either by key or by value.\n", + "\n", + "The dictionary below is a summary of the word frequency of Ed Sheeran's song *Shape of You*. Each key is a word in the lyrics and the value is the number of times that word appears in the lyrics." + ] + }, + { + "cell_type": "code", + "execution_count": null, + "metadata": {}, + "outputs": [], + "source": [ + "word_freq = {'love': 25, 'conversation': 1, 'every': 6, \"we're\": 1, 'plate': 1, 'sour': 1, 'jukebox': 1, 'now': 11, 'taxi': 1, 'fast': 1, 'bag': 1, 'man': 1, 'push': 3, 'baby': 14, 'going': 1, 'you': 16, \"don't\": 2, 'one': 1, 'mind': 2, 'backseat': 1, 'friends': 1, 'then': 3, 'know': 2, 'take': 1, 'play': 1, 'okay': 1, 'so': 2, 'begin': 1, 'start': 2, 'over': 1, 'body': 17, 'boy': 2, 'just': 1, 'we': 7, 'are': 1, 'girl': 2, 'tell': 1, 'singing': 2, 'drinking': 1, 'put': 3, 'our': 1, 'where': 1, \"i'll\": 1, 'all': 1, \"isn't\": 1, 'make': 1, 'lover': 1, 'get': 1, 'radio': 1, 'give': 1, \"i'm\": 23, 'like': 10, 'can': 1, 'doing': 2, 'with': 22, 'club': 1, 'come': 37, 'it': 1, 'somebody': 2, 'handmade': 2, 'out': 1, 'new': 6, 'room': 3, 'chance': 1, 'follow': 6, 'in': 27, 'may': 2, 'brand': 6, 'that': 2, 'magnet': 3, 'up': 3, 'first': 1, 'and': 23, 'pull': 3, 'of': 6, 'table': 1, 'much': 2, 'last': 3, 'i': 6, 'thrifty': 1, 'grab': 2, 'was': 2, 'driver': 1, 'slow': 1, 'dance': 1, 'the': 18, 'say': 2, 'trust': 1, 'family': 1, 'week': 1, 'date': 1, 'me': 10, 'do': 3, 'waist': 2, 'smell': 3, 'day': 6, 'although': 3, 'your': 21, 'leave': 1, 'want': 2, \"let's\": 2, 'lead': 6, 'at': 1, 'hand': 1, 'how': 1, 'talk': 4, 'not': 2, 'eat': 1, 'falling': 3, 'about': 1, 'story': 1, 'sweet': 1, 'best': 1, 'crazy': 2, 'let': 1, 'too': 5, 'van': 1, 'shots': 1, 'go': 2, 'to': 2, 'a': 8, 'my': 33, 'is': 5, 'place': 1, 'find': 1, 'shape': 6, 'on': 40, 'kiss': 1, 'were': 3, 'night': 3, 'heart': 3, 'for': 3, 'discovering': 6, 'something': 6, 'be': 16, 'bedsheets': 3, 'fill': 2, 'hours': 2, 'stop': 1, 'bar': 1}" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "#### Sort the keys of `word_freq` ascendingly.\n", + "\n", + "Please create a new dictionary called `word_freq2` based on `word_freq` with the keys sorted ascedingly.\n", + "\n", + "There are several ways to achieve that goal but many of the ways are beyond what we have covered so far in the course. There is one way that we'll describe employing what you have learned. Please feel free to use this way or any other way you want.\n", + "\n", + "1. First extract the keys of `word_freq` and convert it to a list called `keys`.\n", + "\n", + "1. Sort the `keys` list.\n", + "\n", + "1. Create an empty dictionary `word_freq2`.\n", + "\n", + "1. Use a FOR loop to iterate each value in `keys`. For each key iterated, find the corresponding value in `word_freq` and insert the key-value pair to `word_freq2`.\n", + "\n", + "📖 [Documentation for a for loop](https://docs.python.org/3/reference/compound_stmts.html#for)\n", + "\n", + "Print out `word_freq2` to examine its keys and values. Your output should be:\n", + "\n", + "```python\n", + "{'a': 8, 'about': 1, 'all': 1, 'although': 3, 'and': 23, 'are': 1, 'at': 1, 'baby': 14, 'backseat': 1, 'bag': 1, 'bar': 1, 'be': 16, 'bedsheets': 3, 'begin': 1, 'best': 1, 'body': 17, 'boy': 2, 'brand': 6, 'can': 1, 'chance': 1, 'club': 1, 'come': 37, 'conversation': 1, 'crazy': 2, 'dance': 1, 'date': 1, 'day': 6, 'discovering': 6, 'do': 3, 'doing': 2, \"don't\": 2, 'drinking': 1, 'driver': 1, 'eat': 1, 'every': 6, 'falling': 3, 'family': 1, 'fast': 1, 'fill': 2, 'find': 1, 'first': 1, 'follow': 6, 'for': 3, 'friends': 1, 'get': 1, 'girl': 2, 'give': 1, 'go': 2, 'going': 1, 'grab': 2, 'hand': 1, 'handmade': 2, 'heart': 3, 'hours': 2, 'how': 1, 'i': 6, \"i'll\": 1, \"i'm\": 23, 'in': 27, 'is': 5, \"isn't\": 1, 'it': 1, 'jukebox': 1, 'just': 1, 'kiss': 1, 'know': 2, 'last': 3, 'lead': 6, 'leave': 1, 'let': 1, \"let's\": 2, 'like': 10, 'love': 25, 'lover': 1, 'magnet': 3, 'make': 1, 'man': 1, 'may': 2, 'me': 10, 'mind': 2, 'much': 2, 'my': 33, 'new': 6, 'night': 3, 'not': 2, 'now': 11, 'of': 6, 'okay': 1, 'on': 40, 'one': 1, 'our': 1, 'out': 1, 'over': 1, 'place': 1, 'plate': 1, 'play': 1, 'pull': 3, 'push': 3, 'put': 3, 'radio': 1, 'room': 3, 'say': 2, 'shape': 6, 'shots': 1, 'singing': 2, 'slow': 1, 'smell': 3, 'so': 2, 'somebody': 2, 'something': 6, 'sour': 1, 'start': 2, 'stop': 1, 'story': 1, 'sweet': 1, 'table': 1, 'take': 1, 'talk': 4, 'taxi': 1, 'tell': 1, 'that': 2, 'the': 18, 'then': 3, 'thrifty': 1, 'to': 2, 'too': 5, 'trust': 1, 'up': 3, 'van': 1, 'waist': 2, 'want': 2, 'was': 2, 'we': 7, \"we're\": 1, 'week': 1, 'were': 3, 'where': 1, 'with': 22, 'you': 16, 'your': 21}\n", + "```" + ] + }, + { + "cell_type": "code", + "execution_count": null, + "metadata": {}, + "outputs": [], + "source": [ + "# Your code here" + ] + }, + { + "cell_type": "markdown", + "metadata": {}, + "source": [ + "#### Sort the values of `word_freq` ascendingly.\n", + "\n", + "Sorting the values of a dictionary is more tricky than sorting the keys because a dictionary's values are not unique. Therefore you cannot use the same way you sorted dict keys to sort dict values.\n", + "\n", + "The way to sort a dict by value is to utilize the `sorted` and `operator.itemgetter` functions. The following code snippet is provided to you to try. It will give you a list of tuples in which each tuple contains the key and value of a dict item. And the list is sorted based on the dict value ( [reference](http://thomas-cokelaer.info/blog/2017/12/how-to-sort-a-dictionary-by-values-in-python/)\n", + ").\n", + "\n", + "```python\n", + "import operator\n", + "sorted_tups = sorted(word_freq.items(), key=operator.itemgetter(1))\n", + "print(sorted_tups)\n", + "```\n", + "\n", + "Therefore, the steps to sort `word_freq` by value are:\n", + "\n", + "* Using `sorted` and `operator.itemgetter`, obtain a list of tuples of the dict key-value pairs which is sorted on the value.\n", + "\n", + "* Create an empty dictionary named `word_freq2`.\n", + "\n", + "* Iterate the list of tuples. Insert each key-value pair into `word_freq2` as an object.\n", + "\n", + "Print `word_freq2` to confirm your dictionary has its values sorted. Your output should be:\n", + "\n", + "```python\n", + "{'conversation': 1, \"we're\": 1, 'plate': 1, 'sour': 1, 'jukebox': 1, 'taxi': 1, 'fast': 1, 'bag': 1, 'man': 1, 'going': 1, 'one': 1, 'backseat': 1, 'friends': 1, 'take': 1, 'play': 1, 'okay': 1, 'begin': 1, 'over': 1, 'just': 1, 'are': 1, 'tell': 1, 'drinking': 1, 'our': 1, 'where': 1, \"i'll\": 1, 'all': 1, \"isn't\": 1, 'make': 1, 'lover': 1, 'get': 1, 'radio': 1, 'give': 1, 'can': 1, 'club': 1, 'it': 1, 'out': 1, 'chance': 1, 'first': 1, 'table': 1, 'thrifty': 1, 'driver': 1, 'slow': 1, 'dance': 1, 'trust': 1, 'family': 1, 'week': 1, 'date': 1, 'leave': 1, 'at': 1, 'hand': 1, 'how': 1, 'eat': 1, 'about': 1, 'story': 1, 'sweet': 1, 'best': 1, 'let': 1, 'van': 1, 'shots': 1, 'place': 1, 'find': 1, 'kiss': 1, 'stop': 1, 'bar': 1, \"don't\": 2, 'mind': 2, 'know': 2, 'so': 2, 'start': 2, 'boy': 2, 'girl': 2, 'singing': 2, 'doing': 2, 'somebody': 2, 'handmade': 2, 'may': 2, 'that': 2, 'much': 2, 'grab': 2, 'was': 2, 'say': 2, 'waist': 2, 'want': 2, \"let's\": 2, 'not': 2, 'crazy': 2, 'go': 2, 'to': 2, 'fill': 2, 'hours': 2, 'push': 3, 'then': 3, 'put': 3, 'room': 3, 'magnet': 3, 'up': 3, 'pull': 3, 'last': 3, 'do': 3, 'smell': 3, 'although': 3, 'falling': 3, 'were': 3, 'night': 3, 'heart': 3, 'for': 3, 'bedsheets': 3, 'talk': 4, 'too': 5, 'is': 5, 'every': 6, 'new': 6, 'follow': 6, 'brand': 6, 'of': 6, 'i': 6, 'day': 6, 'lead': 6, 'shape': 6, 'discovering': 6, 'something': 6, 'we': 7, 'a': 8, 'like': 10, 'me': 10, 'now': 11, 'baby': 14, 'you': 16, 'be': 16, 'body': 17, 'the': 18, 'your': 21, 'with': 22, \"i'm\": 23, 'and': 23, 'love': 25, 'in': 27, 'my': 33, 'come': 37, 'on': 40}\n", + "```" + ] + }, + { + "cell_type": "code", + "execution_count": null, + "metadata": {}, + "outputs": [], + "source": [ + "# Your code here" + ] + } + ], + "metadata": { + "kernelspec": { + "display_name": "Python 3 (ipykernel)", + "language": "python", + "name": "python3" + }, + "language_info": { + "codemirror_mode": { + "name": "ipython", + "version": 3 + }, + "file_extension": ".py", + "mimetype": "text/x-python", + "name": "python", + "nbconvert_exporter": "python", + "pygments_lexer": "ipython3", + "version": "3.11.13" + }, + "vscode": { + "interpreter": { + "hash": "aee8b7b246df8f9039afb4144a1f6fd8d2ca17a180786b69acc140d282b71a49" + } + } + }, + "nbformat": 4, + "nbformat_minor": 4 +} diff --git a/your-code/challenges.ipynb b/your-code/challenges.ipynb index ba91b3f..b312fc4 100644 --- a/your-code/challenges.ipynb +++ b/your-code/challenges.ipynb @@ -13,11 +13,13 @@ }, { "cell_type": "code", - "execution_count": null, - "metadata": {}, + "execution_count": 1, + "metadata": { + "tags": [] + }, "outputs": [], "source": [ - "# Your code here" + "tup = (\"I\",)" ] }, { @@ -31,11 +33,21 @@ }, { "cell_type": "code", - "execution_count": null, - "metadata": {}, - "outputs": [], + "execution_count": 3, + "metadata": { + "tags": [] + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "\n" + ] + } + ], "source": [ - "# Your code here" + "print(type(tup))" ] }, { @@ -53,16 +65,30 @@ }, { "cell_type": "code", - "execution_count": null, + "execution_count": 5, "metadata": { - "scrolled": true + "scrolled": true, + "tags": [] }, - "outputs": [], + "outputs": [ + { + "ename": "AttributeError", + "evalue": "'tuple' object has no attribute 'append'", + "output_type": "error", + "traceback": [ + "\u001b[1;31m---------------------------------------------------------------------------\u001b[0m", + "\u001b[1;31mAttributeError\u001b[0m Traceback (most recent call last)", + "Cell \u001b[1;32mIn[5], line 2\u001b[0m\n\u001b[0;32m 1\u001b[0m tup \u001b[38;5;241m=\u001b[39m (\u001b[38;5;124m\"\u001b[39m\u001b[38;5;124mI\u001b[39m\u001b[38;5;124m\"\u001b[39m,)\n\u001b[1;32m----> 2\u001b[0m \u001b[43mtup\u001b[49m\u001b[38;5;241;43m.\u001b[39;49m\u001b[43mappend\u001b[49m(\u001b[38;5;124m\"\u001b[39m\u001b[38;5;124mr\u001b[39m\u001b[38;5;124m\"\u001b[39m)\n\u001b[0;32m 4\u001b[0m \u001b[38;5;66;03m# It failed becaused Tuples are immutable and you cannot change their contents.\u001b[39;00m\n\u001b[0;32m 5\u001b[0m \u001b[38;5;66;03m# But to append elements, we can use List which is mutable\u001b[39;00m\n", + "\u001b[1;31mAttributeError\u001b[0m: 'tuple' object has no attribute 'append'" + ] + } + ], "source": [ - "# Your code here\n", + "tup = (\"I\",)\n", + "tup.append(\"r\")\n", "\n", - "# Your explanation here\n", - "# You can :) " + "# It failed becaused Tuples are immutable and you cannot change their contents.\n", + "# But to append elements, we can use List which is mutable" ] }, { @@ -80,11 +106,29 @@ }, { "cell_type": "code", - "execution_count": null, + "execution_count": 7, + "metadata": { + "tags": [] + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "('I', 'r', 'o', 'n', 'h', 'a', 'c', 'k')\n" + ] + } + ], + "source": [ + "tup = (\"I\", \"r\", \"o\", \"n\", \"h\", \"a\", \"c\", \"k\")\n", + "print(tup)" + ] + }, + { + "cell_type": "markdown", "metadata": {}, - "outputs": [], "source": [ - "# Your code here" + "You can re-assign a new value to a tuple variable, because this is not modifying the existing tuple, but rather you are simply making the variable tup point to a new tuple." ] }, { @@ -102,11 +146,29 @@ }, { "cell_type": "code", - "execution_count": null, - "metadata": {}, - "outputs": [], + "execution_count": 10, + "metadata": { + "tags": [] + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "tup1 = ('I', 'r', 'o', 'n')\n", + "tup2 = ('h', 'a', 'c', 'k')\n" + ] + } + ], "source": [ - "# Your code here" + "# Slice using positive indices for tup1 (first 4 elements)\n", + "tup1 = tup[0:4]\n", + "\n", + "# Slice using negative indices for tup2 (last 4 elements)\n", + "tup2 = tup[-4:] \n", + "\n", + "print(\"tup1 =\", tup1)\n", + "print(\"tup2 =\", tup2)" ] }, { @@ -120,11 +182,31 @@ }, { "cell_type": "code", - "execution_count": null, + "execution_count": 12, + "metadata": { + "tags": [] + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "tup: ('I', 'r', 'o', 'n', 'h', 'a', 'c', 'k')\n", + "tup3: ('I', 'r', 'o', 'n', 'h', 'a', 'c', 'k')\n" + ] + } + ], + "source": [ + "tup3 = tup1 + tup2\n", + "print(\"tup: \",tup)\n", + "print(\"tup3: \",tup3)" + ] + }, + { + "cell_type": "markdown", "metadata": {}, - "outputs": [], "source": [ - "# Your code here" + "tup3 is equal to the tup" ] }, { @@ -136,27 +218,53 @@ }, { "cell_type": "code", - "execution_count": null, - "metadata": {}, - "outputs": [], + "execution_count": 14, + "metadata": { + "tags": [] + }, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "The number of elements in tup1 and tup2 is 8\n", + "The number of elements in tup3 is 8\n" + ] + } + ], "source": [ - "# Your code here" + "count_tup1_tup2 = len(tup1) + len(tup2)\n", + "count_tup3 = len(tup3)\n", + "\n", + "print(\"The number of elements in tup1 and tup2 is\", count_tup1_tup2)\n", + "print(\"The number of elements in tup3 is\", count_tup3)" ] }, { "cell_type": "markdown", "metadata": {}, "source": [ - "#### What is the index number of `\"h\"` in `tup3`?" + "#### What is the index number of \"h\" in `tup3`?" ] }, { "cell_type": "code", - "execution_count": null, - "metadata": {}, - "outputs": [], + "execution_count": 16, + "metadata": {}, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "The index number of 'h' in tup3 is 4\n" + ] + } + ], "source": [ - "# Your code here" + "# Your code here\n", + "\n", + "h_index = tup3.index('h')\n", + "print(\"The index number of 'h' in tup3 is\", h_index)" ] }, { @@ -176,20 +284,28 @@ }, { "cell_type": "code", - "execution_count": null, - "metadata": {}, - "outputs": [], - "source": [ - "# Your code here" - ] - }, - { - "cell_type": "code", - "execution_count": null, - "metadata": {}, - "outputs": [], - "source": [ - "# Your code here" + "execution_count": 22, + "metadata": {}, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "True\n", + "False\n", + "True\n", + "False\n", + "False\n" + ] + } + ], + "source": [ + "# Checking through each letter in the list\n", + "letters = [\"a\", \"b\", \"c\", \"d\", \"e\"]\n", + "\n", + "for letter in letters:\n", + " # Check if the letter is present in tup3\n", + " print(letter in tup3)" ] }, { @@ -203,11 +319,25 @@ }, { "cell_type": "code", - "execution_count": null, + "execution_count": 26, "metadata": {}, - "outputs": [], + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "'a' occurs 1 time(s) in tup3.\n", + "'b' occurs 0 time(s) in tup3.\n", + "'c' occurs 1 time(s) in tup3.\n", + "'d' occurs 0 time(s) in tup3.\n", + "'e' occurs 0 time(s) in tup3.\n" + ] + } + ], "source": [ - "# Your code here" + "for letter in letters:\n", + " count = tup3.count(letter)\n", + " print(f\"'{letter}' occurs {count} time(s) in tup3.\")" ] }, { @@ -223,7 +353,7 @@ }, { "cell_type": "code", - "execution_count": null, + "execution_count": 28, "metadata": {}, "outputs": [], "source": [ @@ -248,11 +378,22 @@ }, { "cell_type": "code", - "execution_count": null, + "execution_count": 30, "metadata": {}, - "outputs": [], + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "[85, 53, 7, 65, 64, 52, 35, 48, 13, 75, 41, 22, 43, 2, 94, 91, 76, 38, 86, 82, 4, 54, 59, 81, 88, 39, 30, 3, 15, 98, 74, 78, 83, 33, 37, 47, 34, 58, 29, 80, 72, 25, 6, 44, 10, 1, 51, 28, 23, 55, 40, 100, 92, 19, 27, 5, 32, 63, 45, 95, 26, 97, 87, 60, 62, 56, 73, 84, 67, 14, 31, 20, 21, 42, 24, 68, 49, 0, 69, 99]\n" + ] + } + ], "source": [ - "# Your code here" + "# Creating a list of 80 unique random integers between 0 and 100\n", + "sample_list_1 = random.sample(range(0, 101), 80)\n", + "\n", + "print(sample_list_1)" ] }, { @@ -264,11 +405,22 @@ }, { "cell_type": "code", - "execution_count": null, + "execution_count": 32, "metadata": {}, - "outputs": [], + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "Length of set1: 80\n" + ] + } + ], "source": [ - "# your code here" + "# Converting the list to a set\n", + "set1 = set(sample_list_1)\n", + "\n", + "print(\"Length of set1:\", len(set1))" ] }, { @@ -287,11 +439,25 @@ }, { "cell_type": "code", - "execution_count": null, + "execution_count": 34, "metadata": {}, - "outputs": [], + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "[92, 3, 9, 3, 78, 42, 78, 41, 12, 14, 34, 10, 93, 55, 69, 28, 87, 48, 85, 76, 57, 85, 42, 58, 21, 16, 97, 97, 67, 9, 6, 6, 57, 53, 41, 10, 74, 47, 45, 19, 5, 7, 47, 84, 61, 36, 44, 96, 69, 72, 86, 36, 37, 49, 1, 70, 18, 17, 58, 5, 62, 67, 33, 20, 0, 56, 38, 47, 3, 76, 31, 28, 54, 66, 3, 11, 0, 76, 33, 33]\n" + ] + } + ], "source": [ - "# your code here" + "# Creating an empty list\n", + "sample_list_2 = []\n", + "\n", + "# Using for loop to append 80 random integers between 0 and 100\n", + "for i in range(80):\n", + " sample_list_2.append(random.randint(0, 100))\n", + "print(sample_list_2)" ] }, { @@ -303,11 +469,22 @@ }, { "cell_type": "code", - "execution_count": null, + "execution_count": 36, "metadata": {}, - "outputs": [], + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "Length of set2: 55\n" + ] + } + ], "source": [ - "# Your code here" + "# Converting the list to a set\n", + "set2 = set(sample_list_2)\n", + "\n", + "print(\"Length of set2:\", len(set2))" ] }, { @@ -319,11 +496,23 @@ }, { "cell_type": "code", - "execution_count": null, + "execution_count": 38, "metadata": {}, - "outputs": [], + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "Elements in set1 but not in set2: {2, 4, 13, 15, 22, 23, 24, 25, 26, 27, 29, 30, 32, 35, 39, 40, 43, 51, 52, 59, 60, 63, 64, 65, 68, 73, 75, 80, 81, 82, 83, 88, 91, 94, 95, 98, 99, 100}\n" + ] + } + ], "source": [ - "# Your code here" + "# Identifying elements present in set1 but not in set2\n", + "set3 = set1 - set2\n", + "\n", + "# Print the result\n", + "print(\"Elements in set1 but not in set2:\", set3)" ] }, { @@ -335,11 +524,21 @@ }, { "cell_type": "code", - "execution_count": null, + "execution_count": 40, "metadata": {}, - "outputs": [], + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "Elements in set2 but not in set1: {96, 66, 36, 70, 9, 11, 12, 16, 17, 18, 93, 57, 61}\n" + ] + } + ], "source": [ - "# Your code here" + "# Identifying elements present in set2 but not in set1\n", + "set4 = set2 - set1\n", + "print(\"Elements in set2 but not in set1:\", set4)" ] }, { @@ -351,11 +550,22 @@ }, { "cell_type": "code", - "execution_count": null, + "execution_count": 42, "metadata": {}, - "outputs": [], + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "Elements shared between set1 and set2: {0, 1, 3, 5, 6, 7, 10, 14, 19, 20, 21, 28, 31, 33, 34, 37, 38, 41, 42, 44, 45, 47, 48, 49, 53, 54, 55, 56, 58, 62, 67, 69, 72, 74, 76, 78, 84, 85, 86, 87, 92, 97}\n" + ] + } + ], "source": [ - "# Your code here" + "# Identifying elements shared between set1 and set2\n", + "set5 = set1 & set2\n", + "\n", + "print(\"Elements shared between set1 and set2:\", set5)" ] }, { @@ -375,11 +585,37 @@ }, { "cell_type": "code", - "execution_count": null, - "metadata": {}, - "outputs": [], - "source": [ - "# Your code here" + "execution_count": 44, + "metadata": {}, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "len(set1): 80\n", + "len(set2): 55\n", + "len(set3): 38\n", + "len(set4): 13\n", + "len(set5): 42\n", + "len(set1) == len(set3) + len(set5): True\n", + "len(set2) == len(set4) + len(set5): True\n", + "len(set1.union(set2)) == len(set3) + len(set4) + len(set5): True\n" + ] + } + ], + "source": [ + "# Verifying the relationships\n", + "print(\"len(set1):\", len(set1))\n", + "print(\"len(set2):\", len(set2))\n", + "print(\"len(set3):\", len(set3))\n", + "print(\"len(set4):\", len(set4))\n", + "print(\"len(set5):\", len(set5))\n", + "\n", + "# Check mathematical relationships\n", + "print(\"len(set1) == len(set3) + len(set5):\", len(set1) == len(set3) + len(set5))\n", + "print(\"len(set2) == len(set4) + len(set5):\", len(set2) == len(set4) + len(set5))\n", + "print(\"len(set1.union(set2)) == len(set3) + len(set4) + len(set5):\", \n", + " len(set1.union(set2)) == len(set3) + len(set4) + len(set5))\n" ] }, { @@ -391,11 +627,24 @@ }, { "cell_type": "code", - "execution_count": null, + "execution_count": 46, "metadata": {}, - "outputs": [], + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "set6: set()\n", + "Type of set6: \n" + ] + } + ], "source": [ - "# Your code here" + "# Creating an empty set\n", + "set6 = set()\n", + "\n", + "print(\"set6:\", set6)\n", + "print(\"Type of set6:\", type(set6))" ] }, { @@ -407,11 +656,24 @@ }, { "cell_type": "code", - "execution_count": null, + "execution_count": 48, "metadata": {}, - "outputs": [], + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "set6: {0, 1, 2, 3, 4, 5, 6, 7, 10, 13, 14, 15, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 37, 38, 39, 40, 41, 42, 43, 44, 45, 47, 48, 49, 51, 52, 53, 54, 55, 56, 58, 59, 60, 62, 63, 64, 65, 67, 68, 69, 72, 73, 74, 75, 76, 78, 80, 81, 82, 83, 84, 85, 86, 87, 88, 91, 92, 94, 95, 97, 98, 99, 100}\n", + "Length of set6: 80\n" + ] + } + ], "source": [ - "# Your code here" + "# Adding elements of set3 and set5 to set6\n", + "set6.update(set3, set5)\n", + "\n", + "print(\"set6:\", set6)\n", + "print(\"Length of set6:\", len(set6))" ] }, { @@ -423,11 +685,20 @@ }, { "cell_type": "code", - "execution_count": null, + "execution_count": 50, "metadata": {}, - "outputs": [], + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "True\n" + ] + } + ], "source": [ - "# Your code here" + "# Checking if set1 and set6 are equal\n", + "print(set1 == set6)" ] }, { @@ -439,11 +710,24 @@ }, { "cell_type": "code", - "execution_count": null, + "execution_count": 52, "metadata": {}, - "outputs": [], + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "Does set1 contain set2?: False\n", + "Does set1 contain set3?: True\n" + ] + } + ], "source": [ - "# Your code here" + "# Checking if set2 is a subset of set1\n", + "print(\"Does set1 contain set2?:\", set2.issubset(set1))\n", + "\n", + "# Checking if set3 is a subset of set1\n", + "print(\"Does set1 contain set3?:\", set3.issubset(set1))\n" ] }, { @@ -457,11 +741,26 @@ }, { "cell_type": "code", - "execution_count": null, + "execution_count": 54, "metadata": {}, - "outputs": [], + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "Are the aggregated values equal?: True\n" + ] + } + ], "source": [ - "# Your code here" + "# Aggregating set3, set4, and set5 using the union method\n", + "combined_1 = set3.union(set4, set5)\n", + "\n", + "# Aggregating set1 and set2\n", + "combined_2 = set1.union(set2)\n", + "\n", + "# Checking if both aggregated sets are equal\n", + "print(\"Are the aggregated values equal?:\", combined_1 == combined_2)\n" ] }, { @@ -473,11 +772,24 @@ }, { "cell_type": "code", - "execution_count": null, + "execution_count": 56, "metadata": {}, - "outputs": [], + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "Removed element: 0\n", + "Updated set1: {1, 2, 3, 4, 5, 6, 7, 10, 13, 14, 15, 19, 20, 21, 22, 23, 24, 25, 26, 27, 28, 29, 30, 31, 32, 33, 34, 35, 37, 38, 39, 40, 41, 42, 43, 44, 45, 47, 48, 49, 51, 52, 53, 54, 55, 56, 58, 59, 60, 62, 63, 64, 65, 67, 68, 69, 72, 73, 74, 75, 76, 78, 80, 81, 82, 83, 84, 85, 86, 87, 88, 91, 92, 94, 95, 97, 98, 99, 100}\n" + ] + } + ], "source": [ - "# Your code here" + "# Removing (and returning) an element from set1\n", + "removed_element = set1.pop()\n", + "\n", + "print(\"Removed element:\", removed_element)\n", + "print(\"Updated set1:\", set1)" ] }, { @@ -493,11 +805,25 @@ }, { "cell_type": "code", - "execution_count": null, - "metadata": {}, - "outputs": [], + "execution_count": 58, + "metadata": {}, + "outputs": [ + { + "name": "stdout", + "output_type": "stream", + "text": [ + "Remaining elements in set1: {2, 3, 4, 5, 6, 7, 10, 13, 14, 15, 20, 22, 23, 24, 25, 26, 27, 28, 30, 32, 33, 34, 35, 37, 38, 40, 42, 43, 44, 45, 47, 48, 52, 53, 54, 55, 56, 58, 60, 62, 63, 64, 65, 67, 68, 72, 73, 74, 75, 76, 78, 80, 82, 83, 84, 85, 86, 87, 88, 92, 94, 95, 97, 98, 100}\n" + ] + } + ], "source": [ - "# Your code here" + "list_to_remove = [1, 9, 11, 19, 21, 29, 31, 39, 41, 49, 51, 59, 61, 69, 71, 79, 81, 89, 91, 99]\n", + "\n", + "# Removing each element if present in set1\n", + "for num in list_to_remove:\n", + " set1.discard(num) # .discard() removes safely without raising an error if the element is missing\n", + "\n", + "print(\"Remaining elements in set1:\", set1)\n" ] }, { @@ -616,7 +942,7 @@ "name": "python", "nbconvert_exporter": "python", "pygments_lexer": "ipython3", - "version": "3.9.13" + "version": "3.11.13" }, "vscode": { "interpreter": { @@ -625,5 +951,5 @@ } }, "nbformat": 4, - "nbformat_minor": 2 + "nbformat_minor": 4 }