Pitfall06-order of if statements

if a1 = a2:
  print('a1=a2')
  
if a1 = a2 and b1 = b2:
  print('a1=a2 and b1=b2')
  
################################################################################################################################# the sequence matters
############################################################################################### most restrict if condition goes first !!!!!!!!!!!!!!!!!!!!!!
in case of a1 = a2 and b1 = b2, it will never print 'a1=a2 and b1=b2'
it will enter into the 1st if statement and execute and end the program!!!!!!!!


def myfunc(a1,a2,b1,b2):
    if a1 == a2:
        print('aaa')
    elif a1 == a2 and b1 == b2:
        print('abab')
    elif b1 == b2:
        print('bbb')
        
a1 = 1
a2 = 1
b1 = 2
b2 = 2

myfunc(a1,a2,b1,b2) -> aaa