diff --git a/02_activities/assignments/Cohort_8/assignment1/Farmers market logical model.drawio.png b/02_activities/assignments/Cohort_8/assignment1/Farmers market logical model.drawio.png new file mode 100644 index 000000000..7f9cf7408 Binary files /dev/null and b/02_activities/assignments/Cohort_8/assignment1/Farmers market logical model.drawio.png differ diff --git a/02_activities/assignments/Cohort_8/assignment1/assignment1.sql b/02_activities/assignments/Cohort_8/assignment1/assignment1.sql new file mode 100644 index 000000000..4857e0d8a --- /dev/null +++ b/02_activities/assignments/Cohort_8/assignment1/assignment1.sql @@ -0,0 +1,160 @@ +/* ASSIGNMENT 1 */ +/* SECTION 2 */ + + +--SELECT +/* 1. Write a query that returns everything in the customer table. */ +SELECT * FROM customer; + + +/* 2. Write a query that displays all of the columns and 10 rows from the cus- tomer table, +sorted by customer_last_name, then customer_first_ name. */ +SELECT * +FROM customer +ORDER BY customer_last_name, customer_first_name +LIMIT 10; + + +--WHERE +/* 1. Write a query that returns all customer purchases of product IDs 4 and 9. */ +SELECT * +FROM purchases +WHERE product_id IN (4, 9); + + +/*2. Write a query that returns all customer purchases and a new calculated column 'price' (quantity * cost_to_customer_per_qty), +filtered by customer IDs between 8 and 10 (inclusive) using either: + 1. two conditions using AND + 2. one condition using BETWEEN +*/ +-- option 1 + SELECT *, + (quantity * cost_to_customer_per_qty) AS price +FROM customer_purchases +WHERE customer_id >= 8 + AND customer_id <= 10; + +-- option 2 +SELECT *, + (quantity * cost_to_customer_per_qty) AS price +FROM customer_purchases +WHERE customer_id BETWEEN 8 AND 10; + + +--CASE +/* 1. Products can be sold by the individual unit or by bulk measures like lbs. or oz. +Using the product table, write a query that outputs the product_id and product_name +columns and add a column called prod_qty_type_condensed that displays the word “unit” +if the product_qty_type is “unit,” and otherwise displays the word “bulk.” */ +SELECT + product_id, + product_name, + CASE + WHEN product_qty_type = 'unit' THEN 'unit' + ELSE 'bulk' + END AS prod_qty_type_condensed +FROM product; + + +/* 2. We want to flag all of the different types of pepper products that are sold at the market. +add a column to the previous query called pepper_flag that outputs a 1 if the product_name +contains the word “pepper” (regardless of capitalization), and otherwise outputs 0. */ +SELECT *, + (quantity * cost_to_customer_per_qty) AS price, + CASE + WHEN LOWER(product_name) LIKE '%pepper%' THEN 1 + ELSE 0 + END AS pepper_flag +FROM customer_purchases +WHERE customer_id BETWEEN 8 AND 10; + + +--JOIN +/* 1. Write a query that INNER JOINs the vendor table to the vendor_booth_assignments table on the +vendor_id field they both have in common, and sorts the result by vendor_name, then market_date. */ +SELECT * +FROM vendor v +INNER JOIN vendor_booth_assignments vba + ON v.vendor_id = vba.vendor_id +ORDER BY v.vendor_name, vba.market_date; + + + +/* SECTION 3 */ + +-- AGGREGATE +/* 1. Write a query that determines how many times each vendor has rented a booth +at the farmer’s market by counting the vendor booth assignments per vendor_id. */ +SELECT + vendor_id, + COUNT(*) AS booth_rental_count +FROM vendor_booth_assignments +GROUP BY vendor_id; + + +/* 2. The Farmer’s Market Customer Appreciation Committee wants to give a bumper +sticker to everyone who has ever spent more than $2000 at the market. Write a query that generates a list +of customers for them to give stickers to, sorted by last name, then first name. + +HINT: This query requires you to join two tables, use an aggregate function, and use the HAVING keyword. */ +SELECT + c.customer_id, + c.customer_last_name, + c.customer_first_name, + SUM(p.quantity * p.cost_to_customer_per_qty) AS total_spent +FROM customer c +JOIN customer_purchases p + ON c.customer_id = p.customer_id +GROUP BY + c.customer_id, + c.customer_last_name, + c.customer_first_name +HAVING SUM(p.quantity * p.cost_to_customer_per_qty) > 2000 +ORDER BY + c.customer_last_name, + c.customer_first_name; + + +--Temp Table +/* 1. Insert the original vendor table into a temp.new_vendor and then add a 10th vendor: +Thomass Superfood Store, a Fresh Focused store, owned by Thomas Rosenthal + +HINT: This is two total queries -- first create the table from the original, then insert the new 10th vendor. +When inserting the new vendor, you need to appropriately align the columns to be inserted +(there are five columns to be inserted, I've given you the details, but not the syntax) + +-> To insert the new row use VALUES, specifying the value you want for each column: +VALUES(col1,col2,col3,col4,col5) +*/ +CREATE TEMP TABLE temp.new_vendor AS +SELECT * +FROM vendor; + +INSERT INTO temp.new_vendor (vendor_id, vendor_name, vendor_type, vendor_description) +VALUES (10, 'Thomass Superfood Store', 'Fresh Focused', 'Owner: Thomas Rosenthal'); + + +-- Date +/*1. Get the customer_id, month, and year (in separate columns) of every purchase in the customer_purchases table. + +HINT: you might need to search for strfrtime modifers sqlite on the web to know what the modifers for month +and year are! */ +SELECT + customer_id, + STRFTIME('%m', purchase_date) AS purchase_month, + STRFTIME('%Y', purchase_date) AS purchase_year +FROM customer_purchases; + + +/* 2. Using the previous query as a base, determine how much money each customer spent in April 2022. +Remember that money spent is quantity*cost_to_customer_per_qty. + +HINTS: you will need to AGGREGATE, GROUP BY, and filter... +but remember, STRFTIME returns a STRING for your WHERE statement!! */ +SELECT + customer_id, + SUM(quantity * cost_to_customer_per_qty) AS total_spent +FROM customer_purchases +WHERE STRFTIME('%m', purchase_date) = '04' + AND STRFTIME('%Y', purchase_date) = '2022' +GROUP BY customer_id;