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:RInlineTemp does not work if the local variable is assigned again #24

@tcrayford

Description

@tcrayford

On the first line of:

x = 5
foo = x + 10
x = 10
bar = x + 10

Doing RInlineTemp gives me:

foo = x + 10
5 = 10
bar = x + 10

It should result in the following:

foo = 5 + 10
x = 10
bar = x + 10

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