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LeetCode 461. Hamming Distance.html
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<h2 id="461-Hamming-Distance（汉明距离）"><a href="#461-Hamming-Distance（汉明距离）" class="headerlink" title="461. Hamming Distance（汉明距离）"></a>461. Hamming Distance（汉明距离）</h2><h3 id="链接"><a href="#链接" class="headerlink" title="链接"></a>链接</h3><p><a href="https://leetcode-cn.com/problems/hamming-distance" target="_blank" rel="noopener">https://leetcode-cn.com/problems/hamming-distance</a></p>
<h3 id="题目"><a href="#题目" class="headerlink" title="题目"></a>题目</h3><p>两个整数之间的汉明距离指的是这两个数字对应二进制位不同的位置的数目。</p>
<p>给出两个整数 x 和 y，计算它们之间的汉明距离。</p>
<p>注意：<br>0 ≤ x, y < 231.</p>
<p>示例:</p>
<p> 输入: x = 1, y = 4</p>
<p> 输出: 2</p>
<p> 解释:<br> 1 (0 0 0 1)<br> 4 (0 1 0 0)<br> ↑ ↑</p>
<p>上面的箭头指出了对应二进制位不同的位置。</p>
<h3 id="思路"><a href="#思路" class="headerlink" title="思路"></a>思路</h3><p>这题的名词也就是转换一下，需要我们找到二进制位的不同，这时候异或最简单，直接找到不同位，然后可以按位寻找，也可以直接和1进行与运算，然后右移。</p>
<h3 id="代码"><a href="#代码" class="headerlink" title="代码"></a>代码</h3><figure class="highlight plain"><table><tr><td class="gutter"><pre><span class="line">1</span><br><span class="line">2</span><br><span class="line">3</span><br><span class="line">4</span><br><span class="line">5</span><br><span class="line">6</span><br><span class="line">7</span><br><span class="line">8</span><br><span class="line">9</span><br><span class="line">10</span><br><span class="line">11</span><br></pre></td><td class="code"><pre><span class="line"> public static int hammingDistance(int x, int y) {</span><br><span class="line"> int xor = x ^ y;</span><br><span class="line"> int num = 0;</span><br><span class="line"> while (xor != 0) {</span><br><span class="line"> if ((xor & 1) == 1) {</span><br><span class="line"> num++;</span><br><span class="line"> }</span><br><span class="line"> xor = xor >> 1;</span><br><span class="line"> }</span><br><span class="line"> return num;</span><br><span class="line">}</span><br></pre></td></tr></table></figure>
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