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fix(docs): merge_chains documentation
- it's a small fix for `merge_chains` docs, reported on audit. - adds an `Errors` section to cover what scenarios it can fail.
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crates/chain/src/local_chain.rs

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@@ -545,31 +545,44 @@ impl std::error::Error for ApplyHeaderError {}
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/// Applies `update_tip` onto `original_tip`.
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///
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/// On success, a tuple is returned `(changeset, can_replace)`. If `can_replace` is true, then the
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/// `update_tip` can replace the `original_tip`.
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/// On success, a tuple is returned ([`CheckPoint`], [`ChangeSet`]).
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///
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/// # Errors
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///
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/// [`CannotConnectError`] occurs when the `original_tip` and `update_tip` chains are disjoint:
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///
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/// - If no point of agreement is found between the update and original chains.
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/// - A point of agreement is found but we were unable to invalidate heights of the original chain.
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/// - A point of agreement is found but we failed to apply the changeset to `CheckPoint`.
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fn merge_chains(
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original_tip: CheckPoint,
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update_tip: CheckPoint,
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) -> Result<(CheckPoint, ChangeSet), CannotConnectError> {
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let mut changeset = ChangeSet::default();
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let mut orig = original_tip.iter();
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let mut update = update_tip.iter();
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let mut curr_orig = None;
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let mut curr_update = None;
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let mut prev_orig: Option<CheckPoint> = None;
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let mut prev_update: Option<CheckPoint> = None;
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let mut point_of_agreement_found = false;
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let mut prev_orig_was_invalidated = false;
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let mut potentially_invalidated_heights = vec![];
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// If we can, we want to return the update tip as the new tip because this allows checkpoints
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// in multiple locations to keep the same `Arc` pointers when they are being updated from each
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// other using this function. We can do this as long as long as the update contains every
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// other using this function. We can do this as long as the update contains every
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// block's height of the original chain.
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let mut is_update_height_superset_of_original = true;
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// To find the difference between the new chain and the original we iterate over both of them
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// from the tip backwards in tandem. We always dealing with the highest one from either chain
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// from the tip backwards in tandem. We are always dealing with the highest one from either chain
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// first and move to the next highest. The crucial logic is applied when they have blocks at the
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// same height.
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loop {

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