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| 1 | +// https://leetcode.com/problems/largest-number-after-digit-swaps-by-parity |
| 2 | +// T: O(log(n) log(log(n))) |
| 3 | +// S: O(log(n)) |
| 4 | + |
| 5 | +import java.util.ArrayList; |
| 6 | +import java.util.Comparator; |
| 7 | +import java.util.List; |
| 8 | + |
| 9 | +public class LargestNumberAfterDigitSwapsByParity { |
| 10 | + public int largestInteger(int num) { |
| 11 | + final String number = num + ""; |
| 12 | + final List<Integer> evenDigits = getEvenDigits(number); |
| 13 | + final List<Integer> oddDigits = getOddDigits(number); |
| 14 | + |
| 15 | + evenDigits.sort(Comparator.reverseOrder()); |
| 16 | + oddDigits.sort(Comparator.reverseOrder()); |
| 17 | + |
| 18 | + final StringBuilder result = new StringBuilder(); |
| 19 | + for (int i = 0, evenIndex = 0, oddIndex = 0; i < number.length() ; i++) { |
| 20 | + if (isOddDigit(number, i)) { |
| 21 | + result.append(oddDigits.get(oddIndex++)); |
| 22 | + } else { |
| 23 | + result.append(evenDigits.get(evenIndex++)); |
| 24 | + } |
| 25 | + } |
| 26 | + |
| 27 | + return Integer.parseInt(result.toString()); |
| 28 | + } |
| 29 | + |
| 30 | + private boolean isOddDigit(String number, int index) { |
| 31 | + return (number.charAt(index) - '0') % 2 == 1; |
| 32 | + } |
| 33 | + |
| 34 | + private List<Integer> getEvenDigits(String string) { |
| 35 | + final List<Integer> result = new ArrayList<>(); |
| 36 | + for (int index = 0 ; index < string.length() ; index++) { |
| 37 | + if (!isOddDigit(string, index)) result.add(string.charAt(index) - '0'); |
| 38 | + } |
| 39 | + return result; |
| 40 | + } |
| 41 | + |
| 42 | + private List<Integer> getOddDigits(String string) { |
| 43 | + final List<Integer> result = new ArrayList<>(); |
| 44 | + for (int index = 0 ; index < string.length() ; index++) { |
| 45 | + if (isOddDigit(string, index)) result.add(string.charAt(index) - '0'); |
| 46 | + } |
| 47 | + return result; |
| 48 | + } |
| 49 | +} |
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