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// 递归求一半的值 double result = powerWithUnsignedExponent(base, exponent >> 2); 这里应该是右移一位,改为 double result = powerWithUnsignedExponent(base, exponent >> 1);
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// 递归求一半的值
double result = powerWithUnsignedExponent(base, exponent >> 2);
这里应该是右移一位,改为
double result = powerWithUnsignedExponent(base, exponent >> 1);
The text was updated successfully, but these errors were encountered: