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Adding Simple Solution for Problem - 70 - Climbing Stairs
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##==================================
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## Leetcode
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## Student: Vandit Jyotindra Gajjar
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## Year: 2020
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## Problem: 73
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## Problem Name: Set Matrix Zeroes
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##===================================
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#Given a m x n matrix, if an element is 0, set its entire row and column to 0. Do it in-place.
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#
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#Example 1:
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#
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#Input:
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#[
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# [1,1,1],
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# [1,0,1],
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# [1,1,1]
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#]
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#Output:
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#[
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# [1,0,1],
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# [0,0,0],
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# [1,0,1]
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#]
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#Example 2:
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#
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#Input:
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#[
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# [0,1,2,0],
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# [3,4,5,2],
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# [1,3,1,5]
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#]
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#Output:
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#[
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# [0,0,0,0],
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# [0,4,5,0],
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# [0,3,1,0]
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#]
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class Solution:
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def setZeroes(self, matrix):
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i, j = len(matrix), len(matrix[0]) #Initialize i, j
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c = False #Initialize bool c
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for row in range(i): #Loop through rows
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if matrix[row][0] == 0: #Condition-check: If row contains any zero element
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c = True #Update c to True
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for column in range(1, j): #Loop through column
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if matrix[row][column] == 0: #Condition-check: If row and column has zero element
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matrix[row][0] = 0 #Set row to zero
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matrix[column][0] = 0 #Set column to zero
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for row in range(1, i): #Loop through row
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for column in range(1, j): #Loop through column
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if not matrix[row][0] or not matrix[0][column]: #Condition-check: If row and matrix is empty
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matrix[row][column] = 0 #Set row and column to zero
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if matrix[0][0] == 0: #Condition-check: If 0th element row and column wise found
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for column in range(j): #Loop through column
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matrix[0][column] = 0: #set column to zero
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if c: #Condition-check: If False
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for row in range(i): #Loop through row
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matrix[row][0] = 0 #Set row to zero

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