diff --git a/02_activities/assignments/Assignment 1 Section 1.pdf b/02_activities/assignments/Assignment 1 Section 1.pdf
new file mode 100644
index 000000000..c4221fb13
Binary files /dev/null and b/02_activities/assignments/Assignment 1 Section 1.pdf differ
diff --git a/02_activities/assignments/assignment1.sql b/02_activities/assignments/assignment1.sql
index 2e89fa7af..fd2d5210d 100644
--- a/02_activities/assignments/assignment1.sql
+++ b/02_activities/assignments/assignment1.sql
@@ -4,21 +4,29 @@
 
 --SELECT
 /* 1. Write a query that returns everything in the customer table. */
-
+SELECT*
+FROM customer
 
 
 /* 2. Write a query that displays all of the columns and 10 rows from the cus- tomer table, 
 sorted by customer_last_name, then customer_first_ name. */
-
+SELECT*
+FROM customer
+ORDER BY customer_last_name, customer_first_name 
+LIMIT 10
 
 
 --WHERE
 /* 1. Write a query that returns all customer purchases of product IDs 4 and 9. */
 -- option 1
-
+SELECT*
+FROM customer_purchases
+WHERE product_id=4 OR product_id=9
 
 -- option 2
-
+SELECT *
+FROM customer_purchases
+WHERE product_id IN (4, 9)
 
 
 /*2. Write a query that returns all customer purchases and a new calculated column 'price' (quantity * cost_to_customer_per_qty), 
@@ -27,10 +35,14 @@ filtered by vendor IDs between 8 and 10 (inclusive) using either:
 	2.  one condition using BETWEEN
 */
 -- option 1
-
+SELECT*, (quantity * cost_to_customer_per_qty) AS price
+FROM customer_purchases
+WHERE vendor_id BETWEEN 8 AND 10
 
 -- option 2
-
+SELECT*, (quantity * cost_to_customer_per_qty) AS price
+FROM customer_purchases
+WHERE vendor_id >= 8 AND vendor_id <= 10
 
 
 --CASE
@@ -39,19 +51,37 @@ Using the product table, write a query that outputs the product_id and product_n
 columns and add a column called prod_qty_type_condensed that displays the word “unit” 
 if the product_qty_type is “unit,” and otherwise displays the word “bulk.” */
 
-
+SELECT product_id, product_name,
+CASE WHEN product_qty_type="lbs"
+		THEN "Unit"
+	ELSE "Bulk"
+	END AS prod_qty_type_condensed
+FROM product
 
 /* 2. We want to flag all of the different types of pepper products that are sold at the market. 
 add a column to the previous query called pepper_flag that outputs a 1 if the product_name 
 contains the word “pepper” (regardless of capitalization), and otherwise outputs 0. */
-
+SELECT product_id, product_name, product_qty_type,
+CASE WHEN product_qty_type="lbs"
+		THEN "Unit"
+	ELSE "Bulk"
+	END AS prod_qty_type_condensed,
+CASE WHEN product_name LIKE "%pepper%"
+		THEN 1
+	ELSE 0
+	END AS pepper_flag
+FROM product
 
 
 --JOIN
 /* 1. Write a query that INNER JOINs the vendor table to the vendor_booth_assignments table on the 
 vendor_id field they both have in common, and sorts the result by vendor_name, then market_date. */
 
-
+SELECT*
+FROM vendor v
+INNER JOIN vendor_booth_assignments vba
+ON v.vendor_id=vba.vendor_id
+ORDER BY vendor_name, market_date
 
 
 /* SECTION 3 */
@@ -60,7 +90,9 @@ vendor_id field they both have in common, and sorts the result by vendor_name, t
 /* 1. Write a query that determines how many times each vendor has rented a booth 
 at the farmer’s market by counting the vendor booth assignments per vendor_id. */
 
-
+SELECT vendor_id, count(vendor_id)
+FROM vendor_booth_assignments
+GROUP BY vendor_id
 
 /* 2. The Farmer’s Market Customer Appreciation Committee wants to give a bumper 
 sticker to everyone who has ever spent more than $2000 at the market. Write a query that generates a list 
@@ -68,6 +100,13 @@ of customers for them to give stickers to, sorted by last name, then first name.
 
 HINT: This query requires you to join two tables, use an aggregate function, and use the HAVING keyword. */
 
+SELECT c.customer_last_name, c.customer_first_name, SUM(quantity*cost_to_customer_per_qty) AS Spent
+FROM customer_purchases cp
+INNER JOIN customer c
+	ON cp.customer_id=c.customer_id
+GROUP BY c.customer_last_name, c.customer_first_name
+HAVING Spent>2000
+ORDER BY c.customer_last_name, c.customer_first_name
 
 
 --Temp Table
@@ -82,7 +121,12 @@ When inserting the new vendor, you need to appropriately align the columns to be
 VALUES(col1,col2,col3,col4,col5) 
 */
 
+CREATE TEMP TABLE new_vendor AS
+SELECT * FROM vendor;
+
 
+INSERT INTO new_vendor (vendor_id, vendor_name, vendor_type, vendor_owner_first_name, vendor_owner_last_name)
+VALUES (10, 'Thomass Superfood Store', 'Fresh Focused', 'Thomas', 'Rosenthal');
 
 -- Date
 /*1. Get the customer_id, month, and year (in separate columns) of every purchase in the customer_purchases table.
@@ -90,7 +134,11 @@ VALUES(col1,col2,col3,col4,col5)
 HINT: you might need to search for strfrtime modifers sqlite on the web to know what the modifers for month 
 and year are! */
 
-
+SELECT 
+  customer_id,
+  strftime('%m', market_date) AS month,
+  strftime('%Y', market_date) AS year
+FROM customer_purchases
 
 /* 2. Using the previous query as a base, determine how much money each customer spent in April 2022. 
 Remember that money spent is quantity*cost_to_customer_per_qty. 
@@ -98,3 +146,12 @@ Remember that money spent is quantity*cost_to_customer_per_qty.
 HINTS: you will need to AGGREGATE, GROUP BY, and filter...
 but remember, STRFTIME returns a STRING for your WHERE statement!! */
 
+SELECT 
+  customer_id,
+  strftime('%m', market_date) AS month,
+  strftime('%Y', market_date) AS year,
+  SUM(quantity * cost_to_customer_per_qty) AS total_spent
+FROM customer_purchases
+WHERE month = '04'
+  AND year = '2022'
+GROUP BY customer_id;