new projects

Author: Nar0kan

OtherSources/Task_2.ImageByURLSaver.py OtherSources/Task2_Image_By_URL_Saver_old.py

@@ -1,11 +1,11 @@
-#Initialization of variables
+# Initialization of variables
 file1 = open('task_4.txt', 'r')
 spisok = []
 k = 0
 p = 0
 amount = 0
 
-#Input in list numbers from .txt file
+# Input in list numbers from .txt file
 for i in file1:
     spisok.append(i[:-1])
     k+=1
@@ -16,7 +16,7 @@
 print("Загальна кількість елементів: ", k)
 #print(spisok)
 
-#Looping through the numbers in list to find same one's
+# Looping through numbers in the list to find same one's
 while p < k:
     for t in range (0, k):
         if int(new_spisok[p]) == int(new_spisok[t]) and p!=t:
@@ -29,7 +29,7 @@
 
 file2 = open('task_4_result.txt', 'w')
 
-#Output loop in order (bubble)
+# Ordering output loop (bubble method)
 for i in range(0, k):
     for j in range(0, k-1):
         if len(new_spisok[j]) == len(new_spisok[j+1]):
@@ -38,12 +38,13 @@
         elif len(new_spisok[j]) > len(new_spisok[j+1]):
             new_spisok[j], new_spisok[j + 1] = new_spisok[j + 1], new_spisok[j]
 
-#Saving data to file2
+# Saving data to file2
 for i in range(0, k):
     file2.writelines(new_spisok[i])
     file2.writelines('\n')
 
 file2.close()
-#Output the result
+
+# Output the result
 print("Кількість елементів, що повторюються: ", amount)
 #print(new_spisok)

OtherSources/Task4.TxtFilesDuplicateNumbersFinder.py OtherSources/Task4_TxtFiles_Duplicate_Numbers_Finder_old.py

@@ -0,0 +1,31 @@
+from random import randint
+
+# We can use password length and restricted symbols as arguments is this function
+def generate_password(length = 12, restricted_symbols = ""):
+    # Creating variables for symbols (that'll be used in password) and password strings
+    symbols = "abcdefghigklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789/.';\"[]}{|\\?,!#$%^&*@)(-+="
+    password = ""
+
+    # Looping through restricted_symbols to delete such from a symbols string
+    for el in restricted_symbols:
+        try:
+            symbols = symbols[:symbols.find(el)] + symbols[symbols.find(el)+1:]
+        except IndexError:
+            # That means duplicates in restricted symbols variable
+            pass
+    
+    # Looping length of password times to fill the password string
+    for i in range(0, length):
+        password = password + symbols[randint(0, len(symbols))]
+
+    # Returning password string
+    return password
+
+# Some tests:
+if __name__ == "__main__":
+    print(generate_password())
+    print(generate_password(20))
+    print(generate_password(0))
+    print(generate_password(10, "abcABCefgEFGhigHIG"))
+    print(generate_password(10, "AAAAAaaavvv"))
+    print(generate_password(10, ",./?|\\';\""))

OtherSources/password_generator.py

@@ -0,0 +1,40 @@
+# Look on phone number and validate it
+# Format: dddd-dddd-dddd
+
+# w/o RegEx
+def check_phone(number):
+    if len(number) != 14:
+        return False
+    
+    for i in range(0, 4):
+        if not number[i].isdecimal() or not number[i+5].isdecimal() or not number[i+10].isdecimal():
+            return False
+    
+    return True if number[4] == number[9] and number[9] == "-" else False
+
+# with RegEx
+def check_phone_regex(number):
+    from re import findall
+    return True if findall("\d{4}-\d{4}-\d{4}", number) else False
+
+# Some tests:
+
+def test_check_phone_regex():
+    print("\n")
+    print("Test check phone number with regex: ")
+    print(check_phone_regex("9999-2222-1111"))
+    print(check_phone_regex("9999-2222-111"))
+    print(check_phone_regex("9999-2222-11s1"))
+    print(check_phone_regex("9999-222201111"))
+
+def test_check_phone():
+    print("\n")
+    print("Test check phone number no libs: ")
+    print(check_phone("9999-2222-1111"))
+    print(check_phone("9999-2222-111"))
+    print(check_phone("9999-2222-11s1"))
+    print(check_phone("9999-222201111"))
+
+if __name__ == "__main__":
+    test_check_phone()
+    test_check_phone_regex()