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0975-odd-even-jump.js
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/**
* 975. Odd Even Jump
* https://leetcode.com/problems/odd-even-jump/
* Difficulty: Hard
*
* You are given an integer array arr. From some starting index, you can make a series of jumps.
* The (1st, 3rd, 5th, ...) jumps in the series are called odd-numbered jumps, and the (2nd,
* 4th, 6th, ...) jumps in the series are called even-numbered jumps. Note that the jumps are
* numbered, not the indices.
*
* You may jump forward from index i to index j (with i < j) in the following way:
* - During odd-numbered jumps (i.e., jumps 1, 3, 5, ...), you jump to the index j such that
* arr[i] <= arr[j] and arr[j] is the smallest possible value. If there are multiple such
* indices j, you can only jump to the smallest such index j.
* - During even-numbered jumps (i.e., jumps 2, 4, 6, ...), you jump to the index j such that
* arr[i] >= arr[j] and arr[j] is the largest possible value. If there are multiple such
* indices j, you can only jump to the smallest such index j.
* - It may be the case that for some index i, there are no legal jumps.
*
* A starting index is good if, starting from that index, you can reach the end of the array (index
* arr.length - 1) by jumping some number of times (possibly 0 or more than once).
*
* Return the number of good starting indices.
*/
/**
* @param {number[]} arr
* @return {number}
*/
var oddEvenJumps = function(arr) {
const oddCanReach = new Array(arr.length).fill(false);
const evenCanReach = new Array(arr.length).fill(false);
oddCanReach[arr.length - 1] = true;
evenCanReach[arr.length - 1] = true;
let result = 1;
const sortedIndices = Array.from({ length: arr.length }, (_, i) => i);
sortedIndices.sort((a, b) => arr[a] - arr[b] || a - b);
const oddNext = new Array(arr.length);
const evenNext = new Array(arr.length);
const stack = [];
for (const i of sortedIndices) {
while (stack.length && stack[stack.length - 1] < i) {
oddNext[stack.pop()] = i;
}
stack.push(i);
}
sortedIndices.sort((a, b) => arr[b] - arr[a] || a - b);
stack.length = 0;
for (const i of sortedIndices) {
while (stack.length && stack[stack.length - 1] < i) {
evenNext[stack.pop()] = i;
}
stack.push(i);
}
for (let i = arr.length - 2; i >= 0; i--) {
if (oddNext[i] !== undefined) {
oddCanReach[i] = evenCanReach[oddNext[i]];
if (oddCanReach[i]) result++;
}
if (evenNext[i] !== undefined) {
evenCanReach[i] = oddCanReach[evenNext[i]];
}
}
return result;
};