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parallel_bs.cpp
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#pragma GCC optimize("Ofast")
#pragma GCC target("avx,avx2,fma")
#include <bits/stdc++.h>
//#include <ext/pb_ds/assoc_container.hpp> //required
//#include <ext/pb_ds/tree_policy.hpp> //required
//using namespace __gnu_pbds; //required
using namespace std;
//template <typename T> using ordered_set = tree<T, null_type, less<T>, rb_tree_tag, tree_order_statistics_node_update>;
// ordered_set <int> s;
// s.find_by_order(k); returns the (k+1)th smallest element
// s.order_of_key(k); returns the number of elements in s strictly less than k
#define pb push_back
#define mp(x,y) make_pair(x,y)
#define all(x) x.begin(), x.end()
#define print(vec,l,r) for(int i = l; i <= r; i++) cout << vec[i] <<" "; cout << endl;
#define input(vec,N) for(int i = 0; i < (N); i++) cin >> vec[i];
#define leftmost_bit(x) (63-__builtin_clzll(x))
#define rightmost_bit(x) __builtin_ctzll(x) // count trailing zeros
#define set_bits(x) __builtin_popcountll(x)
#define pow2(i) (1LL << (i))
#define is_on(x, i) ((x) & pow2(i)) // state of the ith bit in x
#define set_on(x, i) ((x) | pow2(i)) // returns integer x with ith bit on
#define set_off(x, i) ((x) & ~pow2(i)) // returns integer x with ith bit off
#ifdef LOCAL_DEBUG
#define debug(...) logger(#__VA_ARGS__, __VA_ARGS__)
#else
#define debug(...) ;
#endif
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
// auto dist = uniform_int_distribution<int>(l, r);
// use int a = dist(rng) to get a random number between [l,r] inclusive
template<typename ...Args>
void logger(string vars, Args&&... values) {
cerr << vars << " = ";
string delim = "";
(..., (cerr << delim << values, delim = ", "));
cerr << endl;
}
typedef long long int ll;
typedef long double ld;
const int MOD = 1e9+7; // 998244353;
const int MX = 2e5+5;
const ll INF = 1e18; // not too close to LLONG_MAX
const ld PI = acos((ld)-1);
const ld EPS = 1e-8;
const int dx[4] = {1,0,-1,0}, dy[4] = {0,1,0,-1}; // for every grid problem!!
// highly risky #defines
// #define int ll // disable when you want to make code a bit faster
#define endl '\n' // disable when dealing with interactive problems
typedef vector<int> vi;
typedef pair<int, int> pii;
const int MAXQ = 1 + 1e5;
const int MAXN = 1 + 1e5;
int lo[MAXQ], hi[MAXQ], ans[MAXQ];
vector<int> vec[MAXN];
// vec[mid] holds the value of all queries whose (lo[i] + hi[i])/2 = mid
int N, Q;
void clear(){ // reset
// reset your data strucutres used. Not low,mid,hi or ans
}
void apply(int idx){ //Apply ith update/query
}
bool possible(int idx){ //Check if the condition is satisfied
}
void work(){
for(int i = 0; i < N; i++) vec[i].clear();
for(int i = 0; i < Q; i++){
if(lo[i] <= hi[i]) vec[(lo[i] + hi[i])/2].pb(i);
}
clear();
for(int mid = 0; mid < N; mid++){
apply(mid); // apply the mid-th update
for(int ind: vec[mid]){ //Add appropriate check conditions
if(possible(ind)){ // is the answer possible after performing the first mid updates
ans[ind] = mid; // change as needed
hi[ind] = mid-1;
}
else lo[ind] = mid+1;
}
}
}
void parallel_binary(){
for(int i = 0; i < Q; i++){
lo[i] = 0;
hi[i] = N-1;
ans[i] = -1; // impossible case
}
bool changed = true;
while(changed){ // P(logN)
changed = false;
for(int i = 0; i < Q; i++){
if(lo[i] <= hi[i]){
changed = true;
}
}
work(); // O((N + Q)*cost of data structure)
}
}
// ~stolen~ inspired from https://github.com/Ashishgup1/Competitive-Coding/blob/master/Parallel%20Binary%20Search.cpp
void solve(){
// code starts from here
//https://pastebin.com/2PAh5pMe
// check here for implementation
// Given N updates and Q queries. You know that for a particular query,
// f(query, i) becomes true after the ith update.
// YOu want to find the first i such that f(query, i) is true.
// So for a single query we can binary search on the answer and perform updates one by one.
// This techinque called parallel binary search does it for all queries with logK factor
}
clock_t startTime;
double getCurrentTime() {
return (double)(clock() - startTime) / CLOCKS_PER_SEC;
}
signed main(){
ios_base::sync_with_stdio(false);
cin.tie(NULL);
//startTime = clock();
// mt19937_64 rnd(time(NULL));
int T = 1;
cin >> T;
while(T--){
solve();
}
//cerr << getCurrentTime() << endl;
return 0;
}