diff --git a/02_activities/assignments/assignment1.sql b/02_activities/assignments/assignment1.sql
index 2e89fa7af..7bd13c38f 100644
--- a/02_activities/assignments/assignment1.sql
+++ b/02_activities/assignments/assignment1.sql
@@ -5,21 +5,24 @@
 --SELECT
 /* 1. Write a query that returns everything in the customer table. */
 
-
+SELECT * FROM customer;
 
 /* 2. Write a query that displays all of the columns and 10 rows from the cus- tomer table, 
 sorted by customer_last_name, then customer_first_ name. */
-
-
+SELECT * FROM customer
+ORDER BY customer_last_name,customer_first_name
+LIMIT 10;
 
 --WHERE
 /* 1. Write a query that returns all customer purchases of product IDs 4 and 9. */
 -- option 1
-
+SELECT * FROM customer_purchases
+WHERE product_id = 4 OR product_id = 9;
 
 -- option 2
 
-
+SELECT * FROM customer_purchases
+WHERE product_id IN (4,9);
 
 /*2. Write a query that returns all customer purchases and a new calculated column 'price' (quantity * cost_to_customer_per_qty), 
 filtered by vendor IDs between 8 and 10 (inclusive) using either:
@@ -27,10 +30,12 @@ filtered by vendor IDs between 8 and 10 (inclusive) using either:
 	2.  one condition using BETWEEN
 */
 -- option 1
-
+SELECT *,quantity*cost_to_customer_per_qty AS price FROM customer_purchases
+WHERE vendor_id BETWEEN 8 AND 10;
 
 -- option 2
-
+SELECT *,quantity*cost_to_customer_per_qty AS price FROM customer_purchases
+WHERE vendor_id  >= 8 AND vendor_id <= 10;
 
 
 --CASE
@@ -38,21 +43,37 @@ filtered by vendor IDs between 8 and 10 (inclusive) using either:
 Using the product table, write a query that outputs the product_id and product_name
 columns and add a column called prod_qty_type_condensed that displays the word “unit” 
 if the product_qty_type is “unit,” and otherwise displays the word “bulk.” */
-
-
+SELECT product_id, product_name,
+CASE
+	WHEN product_qty_type = 'unit' THEN 'unit'
+	ELSE 'bulk'
+END AS product_qty_type_condensed
+FROM product;
 
 /* 2. We want to flag all of the different types of pepper products that are sold at the market. 
 add a column to the previous query called pepper_flag that outputs a 1 if the product_name 
 contains the word “pepper” (regardless of capitalization), and otherwise outputs 0. */
 
-
+SELECT product_id, product_name,
+CASE
+	WHEN product_qty_type = 'unit' THEN 'unit'
+	ELSE 'bulk'
+END AS product_qty_type_condensed,
+CASE
+	WHEN lower(product_name) like '%peppers%' THEN 1
+	ELSE 0
+END AS pepper_flag
+FROM product;
 
 --JOIN
 /* 1. Write a query that INNER JOINs the vendor table to the vendor_booth_assignments table on the 
 vendor_id field they both have in common, and sorts the result by vendor_name, then market_date. */
 
-
-
+SELECT vendor.vendor_name, vendor_booth_assignments.market_date
+FROM vendor
+INNER JOIN vendor_booth_assignments ON vendor.vendor_id = 
+vendor_booth_assignments.vendor_id
+ORDER BY vendor_name, market_date;
 
 /* SECTION 3 */
 
@@ -60,7 +81,9 @@ vendor_id field they both have in common, and sorts the result by vendor_name, t
 /* 1. Write a query that determines how many times each vendor has rented a booth 
 at the farmer’s market by counting the vendor booth assignments per vendor_id. */
 
-
+SELECT vendor_id, COUNT(*) AS booth_rental_count
+FROM vendor_booth_assignments
+GROUP BY vendor_id;
 
 /* 2. The Farmer’s Market Customer Appreciation Committee wants to give a bumper 
 sticker to everyone who has ever spent more than $2000 at the market. Write a query that generates a list 
@@ -68,6 +91,16 @@ of customers for them to give stickers to, sorted by last name, then first name.
 
 HINT: This query requires you to join two tables, use an aggregate function, and use the HAVING keyword. */
 
+SELECT 
+    customer_first_name, 
+    customer_last_name,
+    SUM(quantity * cost_to_customer_per_qty) AS total_spent
+FROM customer
+INNER JOIN customer_purchases 
+    ON customer.customer_id = customer_purchases.customer_id
+GROUP BY customer_first_name, customer_last_name
+HAVING SUM(quantity * cost_to_customer_per_qty) > 2000
+ORDER BY customer_last_name, customer_first_name;
 
 
 --Temp Table
@@ -81,8 +114,16 @@ When inserting the new vendor, you need to appropriately align the columns to be
 -> To insert the new row use VALUES, specifying the value you want for each column:
 VALUES(col1,col2,col3,col4,col5) 
 */
+DROP TABLE IF EXISTS new_vendor;
+
+CREATE TEMP TABLE new_vendor AS
+SELECT * 
+FROM vendor;
 
+INSERT INTO new_vendor (vendor_id, vendor_name, vendor_type, vendor_owner_first_name, vendor_owner_last_name)
+VALUES ('10', 'Thomass Superfood Store', 'Fresh Focused', 'Thomas', 'Rosenthal');
 
+SELECT * FROM new_vendor;
 
 -- Date
 /*1. Get the customer_id, month, and year (in separate columns) of every purchase in the customer_purchases table.
diff --git a/02_activities/assignments/relationship_diagram.drawio.pdf b/02_activities/assignments/relationship_diagram.drawio.pdf
new file mode 100644
index 000000000..0438c690c
Binary files /dev/null and b/02_activities/assignments/relationship_diagram.drawio.pdf differ