diff --git a/sql-assessment/README.md b/sql-assessment/README.md
index 3e821fc..42b936e 100644
--- a/sql-assessment/README.md
+++ b/sql-assessment/README.md
@@ -46,7 +46,7 @@ create table campaign_info (
 
 1. Write a query to get the sum of impressions by day.
 2. Write a query to get the top three revenue-generating states in order of best to worst. How much revenue did the third best state generate?
-3. Write a query that shows total cost, impressions, clicks, and revenue of each campaign. Make sure to include the campaign name in the output.
+3. Write a query that shows total cost, impressions, clicks, and revenue of each campaign. Make sure to include the campaign name in the output. 
 4. Write a query to get the number of conversions of Campaign5 by state. Which state generated the most conversions for this campaign?
 5. In your opinion, which campaign was the most efficient, and why?
 
diff --git a/sql-assessment/answers.sql b/sql-assessment/answers.sql
new file mode 100644
index 0000000..0b29bd9
--- /dev/null
+++ b/sql-assessment/answers.sql
@@ -0,0 +1,46 @@
+-- 1. Write a query to get the sum of impressions by day.
+SELECT date, SUM(impressions) AS total_impressions
+FROM marketing_performance
+GROUP BY date
+ORDER BY date;
+
+--2. Write a query to get the top three revenue-generating states in order of best to worst. How much revenue did the third best state generate?
+SELECT state, SUM(revenue) AS total_revenue
+FROM website_revenue
+GROUP BY state
+ORDER BY total_revenue DESC;
+
+--Third best state was Ohio at 37,577 total impressions
+
+
+--3. Write a query that shows total cost, impressions, clicks, and revenue of each campaign. Make sure to include the campaign name in the output.
+SELECT
+    c.Campaign_name,
+    SUM(mp.cost) AS total_cost,
+    SUM(mp.clicks) AS total_clicks,
+    SUM(mp.conversions) AS total_conversions,
+    SUM(mp.impressions) AS total_impressions
+FROM Campaign_info c
+INNER JOIN Marketing_performance mp ON c.ID = mp.campaign_id
+GROUP BY c.name;
+
+
+--4. Write a query to get the number of conversions of Campaign5 by state. Which state generated the most conversions for this campaign?
+SELECT mp.geo, Sum(mp.conversions) AS total_conversions
+FROM marketing_performance AS mp INNER JOIN Campaign_info AS ci ON mp.campaign_id = ci.ID
+WHERE ((([ci].[Campaign_name])='Campaign5'))
+GROUP BY mp.geo
+ORDER BY Count(total_conversions) DESC , [ci].[Campaign_name];
+
+-- Ohio generated the most conversions for campaign5 at 442
+
+
+--5. In your opinion, which campaign was the most efficient, and why?
+
+--campaign5 was the most efficient because it had the lowest cost per conversion at $1.91 among all campaigns. 
+
+--6. Write a query that showcases the best day of the week (e.g., Sunday, Monday, Tuesday, etc.) to run ads.
+SELECT WeekdayName(date) AS day_of_week, AVG(conversions) AS average_conv
+FROM Marketing_performance
+GROUP BY day_of_week
+ORDER BY average_conv DESC;
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