index.js

// 1.1 Create a variable hacker1 with the driver's name./
const hacker1 = prompt("write your name here");
// 1.2 Print "The driver's name is XXXX"./
console.log(`The driver's name is ${hacker1}`);
// 1.3 Create a variable hacker2 with the navigator's name./
const hacker2 = prompt("write your name here");
// 1.4 Print "The navigator's name is YYYY"./
console.log(`The navigator's name is ${hacker2}`);
// The driver has the longest name, it has XX characters./
if (hacker1.length > hacker2.length) {
  console.log(`The driver has the longest name, it has ${hacker1.length} characters`)
}
//It seems that the navigator has the longest name, it has XX characters/
if (hacker2.length > hacker1.length) {
  console.log(`It seems that the navigator has the longest name, it has ${hacker2.length} characters`)
}
//Wow, you both have equally long names, XX characters!./
if (hacker1.length = hacker2.length) {
  console.log(`Wow, you both have equally long names, ${hacker1.length} characters!`)
}
//Print the characters of the driver's name, separated by space, and in capital letters, i.e., "J O H N"./
let result = ""
for (let i = 0; i < hacker1.length; i++) {
  let currentLetter = hacker1[i].toUpperCase()
  // console.log(currentLetter.split("").join(" "));/
  if (i > 0) {
    result += ` ${currentLetter}`;
  } else {
    result += currentLetter
  }
}
console.log(result)
// Print all the characters of the navigator's name in reverse order, i.e., "nhoJ"./
let nameReverse = ""
for (let j = hacker1.length - 1; j >= 0; j--) {
  let letter = hacker1[j];
  nameReverse += letter;
}
console.log(nameReverse)
/*Depending on the lexicographic order of the strings, print:
The driver's name goes first. Yo, the navigator goes first, definitely.
What?! You both have the same name?*/

if (hacker1.localeCompare (hacker2) === -1) {
    console.log(`${hacker1} goes first`);
}else if  (hacker2.localeCompare (hacker1) === -1) {
    console.log(`Yo, ${hacker2} goes first definitely`);
} else {
    console.log("You both have the same name"); 
}